Docker 容器启动命令未获取 .bashrc 变量 [英] Docker Container Start Command Did Not Get .bashrc variables

问题描述

我在启动容器时使用 docker 来执行命令，但似乎没有从 .bashrc 文件中获取环境变量，请给我一些建议.谢谢

I'm using docker to execute a command when starting the container but seems the environment variable did not get from the .bashrc file, please give me some advice. thanks

dockerFile 我将它添加到 .bashrc:echo "export PYTHONPATH=$PYTHONPATH:/models/research:/models/research/slim" >>/root/.bashrc

dockerFile I add this to .bashrc: echo "export PYTHONPATH=$PYTHONPATH:/models/research:/models/research/slim" >> /root/.bashrc

docker-compose.yml 文件:

docker-compose.yml file with:

command: ["python2", "/usr/bin/supervisord", "--nodaemon", "--configuration", "/etc/supervisor/supervisord.conf"]

PS:如果我 exec echo $PYTHPATH 或只是 exec python2/usr/bin/supervisord -c/etc/supervisor/supervisor.conf 从容器中，没有问题.

PS:if I exec echo $PYTHPATH or just exec python2 /usr/bin/supervisord -c /etc/supervisor/supervisor.conf from container, there have not issues.

系统是 Ubuntu 16.04

The System is Ubuntu 16.04

主管配置:

[program:mosquitto-subscrible]
process_name=%(program_name)s_%(process_num)02d
command=python3 detection.py start_mosquitto_subscrible 
autostart=true
autorestart=true
user=root
numprocs=1
directory=/var/www/html/detection
redirect_stderr=true
stdout_logfile=/var/www/html/detection/logs/detection.log

docker-compose.yml

docker-compose.yml

version: '3'
services:
  tensorflow:
    container_name: object-detection
    build:
    context: ./tensorflow
    dockerfile: Dockerfile
    # environment:
    #   - PYTHONPATH=:/models/research:/models/research/slim
    volumes:
      - ./www:/var/www/html:cached
      - ./tensorflow/supervisor:/etc/supervisor/conf.d
    command: ['tail', '-f', '/dev/null']
    # command: ["python2", "-c", "/usr/bin/supervisord", "--nodaemon","--configuration", "/etc/supervisor/supervisord.conf"]

总之，我在Dockfile中写了一个命令 echo "export PYTHONPATH=$PYTHONPATH:/models/research:/models/research/slim" >>/root/.bashrc 可以通过 PYTHON 找到/models/research.

In conclusion, I write a command in Dockfile echo "export PYTHONPATH=$PYTHONPATH:/models/research:/models/research/slim" >> /root/.bashrc to make /models/research can be found by PYTHON.

有一个python模型/models/research/object_detection.

there have a python model /models/research/object_detection.

对于我的主管，命令 python3 detection.py start_mosquitto_subscrible 无法找到 object_detection 模型，如果我仅从 docker-compose 命令启动 supervisord 而不是在 docker 中执行它容器.

with my supervisor, the command python3 detection.py start_mosquitto_subscrible can't find object_detection model if I start supervisord just from docker-compose command instead of exec it inside docker container.

supervisord 需要 python2 启动，我的代码需要 python3

推荐答案

~/.bashrc 不会运行，直到 shell 以交互方式打开，这就是为什么当你执行 docker exec 交互时没有问题的原因，查看 bashrc 文件的前几行:

~/.bashrc wont run untill the shell is opened interactively, that's why no issues when you do docker exec which is interactive, see the first few lines of bashrc file :

# If not running interactively, don't do anything
case $- in
    *i*) ;;
      *) return;;
esac

您需要注释这些行.

如果您只需要一个环境变量，最好从您的容器中获取 PYTHON_PATH 的值，并将完整的变量添加到您的 docker-compose.yml 文件中.

If you just need one Environment variable, better get the value of PYTHON_PATH from your container and add the complete variable to your docker-compose.yml file.

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