java.lang.RuntimeException: Handler (android.os.Handler) 向死线程上的 Handler 发送消息 [英] java.lang.RuntimeException: Handler (android.os.Handler) sending message to a Handler on a dead thread

查看:17
本文介绍了java.lang.RuntimeException: Handler (android.os.Handler) 向死线程上的 Handler 发送消息的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在我的应用中,我使用 IntentService 发送短信.

in my app I'm using IntentService for sending SMS.

    @Override
protected void onHandleIntent(Intent intent) {
    Bundle data = intent.getExtras();
    String[] recipients = null;
    String message = getString(R.string.unknown_event);
    String name = getString(R.string.app_name);
    if (data != null && data.containsKey(Constants.Services.RECIPIENTS)) {
        recipients = data.getStringArray(Constants.Services.RECIPIENTS);
        name = data.getString(Constants.Services.NAME);
        message = data.getString(Constants.Services.MESSAGE);
        for (int i = 0; i < recipients.length; i++) {
            if(!StringUtils.isNullOrEmpty(recipients[i])) {
                try {
                    Intent sendIntent = new Intent(this, SMSReceiver.class);
                    sendIntent.setAction(Constants.SMS.SEND_ACTION);
                    PendingIntent sendPendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, sendIntent, PendingIntent.FLAG_UPDATE_CURRENT);
                    Intent deliveryIntent = new Intent(this, SMSReceiver.class);
                    deliveryIntent.setAction(Constants.SMS.DELIVERED_ACTION);
                    PendingIntent deliveryPendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, deliveryIntent, PendingIntent.FLAG_UPDATE_CURRENT);
                    SmsManager.getDefault().sendTextMessage(recipients[i].trim(), null, "[" + name + "] " + message, sendPendingIntent, deliveryPendingIntent);
                } catch (Exception e) {
                    Log.e(TAG, "sendTextMessage", e);
                    e.printStackTrace();
                    Toast.makeText(this, e.getMessage(), Toast.LENGTH_LONG).show();
                    MainActivity.instance.writeToLogFile(e.getMessage(), System.currentTimeMillis());                       
                }
            }
        }
    }
}

运行应用程序时,出现以下错误:

when running the app, I get the following error:

W/MessageQueue(7180): Handler (android.os.Handler) {42586468} sending message to a Handler on a dead thread
W/MessageQueue(7180): java.lang.RuntimeException: Handler (android.os.Handler) {42586468} sending message to a Handler on a dead thread
W/MessageQueue(7180):   at android.os.MessageQueue.enqueueMessage(MessageQueue.java:294)
W/MessageQueue(7180):   at android.os.Handler.enqueueMessage(Handler.java:618)
W/MessageQueue(7180):   at android.os.Handler.sendMessageAtTime(Handler.java:587)
W/MessageQueue(7180):   at android.os.Handler.sendMessageDelayed(Handler.java:558)
W/MessageQueue(7180):   at android.os.Handler.post(Handler.java:323)
W/MessageQueue(7180):   at android.widget.Toast$TN.hide(Toast.java:367)
W/MessageQueue(7180):   at android.app.ITransientNotification$Stub.onTransact(ITransientNotification.java:55)
W/MessageQueue(7180):   at android.os.Binder.execTransact(Binder.java:351)
W/MessageQueue(7180):   at dalvik.system.NativeStart.run(Native Method)

我的 SMSReceiver 位于另一个类中.我该如何解决这些问题?谢谢;艾尔.

My SMSReceiver is located in another class. How can i solve this problems? Thanks; Eyal.

推荐答案

这里的问题是您正在由 IntentService 管理的线程内创建一个 Toast.系统将使用与该线程关联的Handler 来显示和隐藏Toast.

The problem here is that you are creating a Toast inside a thread that is managed by the IntentService. The system will use the Handler associated with this thread to show and hide the Toast.

首先 Toast 会正确显示,但是当系统试图隐藏它时,在 onHandleIntent 方法完成后,错误sending message to a Handler on一个死线程"将被抛出,因为创建 Toast 的线程不再有效,并且 Toast 不会消失.

First the Toast will be shown correctly, but when the system tries to hide it, after the onHandleIntent method has finished, the error "sending message to a Handler on a dead thread" will be thrown because the thread on which the Toast was created is no longer valid, and the Toast will not disappear.

为避免这种情况,您应该显示 Toast 向主线程发布消息.举个例子:

To avoid this you should show the Toast posting a message to the Main Thread. Here's an example:

    // create a handler to post messages to the main thread
    Handler mHandler = new Handler(getMainLooper());
    mHandler.post(new Runnable() {
        @Override
        public void run() {
            Toast.makeText(getApplicationContext(), "test", Toast.LENGTH_SHORT).show();
        }
    });

这篇关于java.lang.RuntimeException: Handler (android.os.Handler) 向死线程上的 Handler 发送消息的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆