java.lang.RuntimeException的:处理器(android.os.Handler)发送消息到一个处理器上的一个死线程 [英] java.lang.RuntimeException: Handler (android.os.Handler) sending message to a Handler on a dead thread
问题描述
在我的应用程序,我使用IntentService发送短信。
in my app I'm using IntentService for sending SMS.
@Override
protected void onHandleIntent(Intent intent) {
Bundle data = intent.getExtras();
String[] recipients = null;
String message = getString(R.string.unknown_event);
String name = getString(R.string.app_name);
if (data != null && data.containsKey(Constants.Services.RECIPIENTS)) {
recipients = data.getStringArray(Constants.Services.RECIPIENTS);
name = data.getString(Constants.Services.NAME);
message = data.getString(Constants.Services.MESSAGE);
for (int i = 0; i < recipients.length; i++) {
if(!StringUtils.isNullOrEmpty(recipients[i])) {
try {
Intent sendIntent = new Intent(this, SMSReceiver.class);
sendIntent.setAction(Constants.SMS.SEND_ACTION);
PendingIntent sendPendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, sendIntent, PendingIntent.FLAG_UPDATE_CURRENT);
Intent deliveryIntent = new Intent(this, SMSReceiver.class);
deliveryIntent.setAction(Constants.SMS.DELIVERED_ACTION);
PendingIntent deliveryPendingIntent = PendingIntent.getBroadcast(getApplicationContext(), 0, deliveryIntent, PendingIntent.FLAG_UPDATE_CURRENT);
SmsManager.getDefault().sendTextMessage(recipients[i].trim(), null, "[" + name + "] " + message, sendPendingIntent, deliveryPendingIntent);
} catch (Exception e) {
Log.e(TAG, "sendTextMessage", e);
e.printStackTrace();
Toast.makeText(this, e.getMessage(), Toast.LENGTH_LONG).show();
MainActivity.instance.writeToLogFile(e.getMessage(), System.currentTimeMillis());
}
}
}
}
}
运行应用程序时,我收到以下错误:
when running the app, I get the following error:
W/MessageQueue(7180): Handler (android.os.Handler) {42586468} sending message to a Handler on a dead thread
W/MessageQueue(7180): java.lang.RuntimeException: Handler (android.os.Handler) {42586468} sending message to a Handler on a dead thread
W/MessageQueue(7180): at android.os.MessageQueue.enqueueMessage(MessageQueue.java:294)
W/MessageQueue(7180): at android.os.Handler.enqueueMessage(Handler.java:618)
W/MessageQueue(7180): at android.os.Handler.sendMessageAtTime(Handler.java:587)
W/MessageQueue(7180): at android.os.Handler.sendMessageDelayed(Handler.java:558)
W/MessageQueue(7180): at android.os.Handler.post(Handler.java:323)
W/MessageQueue(7180): at android.widget.Toast$TN.hide(Toast.java:367)
W/MessageQueue(7180): at android.app.ITransientNotification$Stub.onTransact(ITransientNotification.java:55)
W/MessageQueue(7180): at android.os.Binder.execTransact(Binder.java:351)
W/MessageQueue(7180): at dalvik.system.NativeStart.run(Native Method)
我的SMSReceiver位于另一个类。 我怎样才能解决这个问题呢? 谢谢; 的Eyal。
My SMSReceiver is located in another class. How can i solve this problems? Thanks; Eyal.
推荐答案
这里的问题是,你正在创建一个吐司
是由<$管理的线程中C $ C> IntentService 。该系统将使用处理程序
与此线程相关的显示和隐藏吐司
。
The problem here is that you are creating a Toast
inside a thread that is managed by the IntentService
. The system will use the Handler
associated with this thread to show and hide the Toast
.
首先,吐司
将正确显示出来,但是当系统试图将其隐藏,在 onHandleIntent
方法后,完成后,发送消息到处理程序上的死线的错误将被抛出,因为在至极线程的吐司
创建不再有效,而吐司
不会消失。
First the Toast
will be shown correctly, but when the system tries to hide it, after the onHandleIntent
method has finished, the error "sending message to a Handler on a dead thread" will be thrown because the thread in wich the Toast
was created is no longer valid, and the Toast
will not disappear.
要避免这种情况,你应该表现出吐司
发布消息到主线程。这里有一个例子:
To avoid this you should show the Toast
posting a message to the Main Thread. Here's an example:
// create a handler to post messages to the main thread
Handler mHandler = new Handler(getMainLooper());
mHandler.post(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(), "test", Toast.LENGTH_SHORT).show();
}
});
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