javascript 按空格拆分字符串，但忽略引号中的空格(注意不要也用冒号拆分) [英] javascript split string by space, but ignore space in quotes (notice not to split by the colon too)

问题描述

我需要帮助将 javascript 中的字符串按空格 (" ") 拆分，忽略引号表达式中的空格.

I need help splitting a string in javascript by space (" "), ignoring space inside quotes expression.

我有这个字符串:

var str = 'Time:"Last 7 Days" Time:"Last 30 Days"';

我希望我的字符串被拆分为 2:

I would expect my string to be split to 2:

['Time:"Last 7 Days"', 'Time:"Last 30 Days"']

但我的代码拆分为 4:

but my code splits to 4:

['Time:', '"Last 7 Days"', 'Time:', '"Last 30 Days"']

这是我的代码:

str.match(/(".*?"|[^"s]+)(?=s*|s*$)/g);

谢谢！

推荐答案

s = 'Time:"Last 7 Days" Time:"Last 30 Days"'
s.match(/(?:[^s"]+|"[^"]*")+/g) 

// -> ['Time:"Last 7 Days"', 'Time:"Last 30 Days"']

说明:

(?:         # non-capturing group
  [^s"]+   # anything that's not a space or a double-quote
  |         #   or…
  "         # opening double-quote
    [^"]*   # …followed by zero or more chacacters that are not a double-quote
  "         # …closing double-quote
)+          # each match is one or more of the things described in the group

原来，要修正你原来的表达方式，你只需要在组上添加一个+:

Turns out, to fix your original expression, you just need to add a + on the group:

str.match(/(".*?"|[^"s]+)+(?=s*|s*$)/g)
#                         ^ here.

这篇关于javascript 按空格拆分字符串，但忽略引号中的空格(注意不要也用冒号拆分)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！