如何在 Python 中连接文本文件? [英] How do I concatenate text files in Python?
问题描述
我有一个包含 20 个文件名的列表,例如 ['file1.txt', 'file2.txt', ...]
.我想编写一个 Python 脚本来将这些文件连接成一个新文件.我可以通过 f = open(...)
打开每个文件,通过调用 f.readline()
逐行读取,然后将每一行写入新文件.看起来不是很优雅"对我来说,尤其是我必须逐行读/写的部分.
I have a list of 20 file names, like ['file1.txt', 'file2.txt', ...]
. I want to write a Python script to concatenate these files into a new file. I could open each file by f = open(...)
, read line by line by calling f.readline()
, and write each line into that new file. It doesn't seem very "elegant" to me, especially the part where I have to read/write line by line.
有没有更优雅"的在 Python 中如何做到这一点?
Is there a more "elegant" way to do this in Python?
推荐答案
应该这样做
对于大文件:
filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
for fname in filenames:
with open(fname) as infile:
for line in infile:
outfile.write(line)
对于小文件:
filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
for fname in filenames:
with open(fname) as infile:
outfile.write(infile.read())
……还有我想到的另一个有趣的:
filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
for line in itertools.chain.from_iterable(itertools.imap(open, filnames)):
outfile.write(line)
遗憾的是,最后一个方法留下了一些打开的文件描述符,GC 无论如何都应该处理这些描述符.我只是觉得很有趣
Sadly, this last method leaves a few open file descriptors, which the GC should take care of anyway. I just thought it was interesting
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