Python连接文本文件 [英] Python concatenate text files

问题描述

我有20个文件名的列表，如 ['file1.txt'，'file2.txt'，...] 。我想编写一个Python脚本来连接这些文件到一个新的文件。我可以通过 f = open（...）打开每个文件，通过调用 f.readline（），并将每行写入该新文件。对我来说，这看起来不是很优雅，尤其是我必须阅读的部分//逐行写。

在Python中是否有更优雅的方式来实现这个功能？

解决方案

对于大文件：

<$ p $打开（'路径/到/输出/文件'，'W'）作为outfile的文件名= ['file1.txt'，'file2.txt'，...]
：
用于文件名中的fname：
以open（fname）作为infile：
用于infile中的行：
outfile.write（line）

  
 
  
 code> filenames = ['file1.txt'，'file2.txt'，...] 
打开（'path / to / output / file'，'w'）作为outfile：
为文件名中的fname：
以open（fname）作为infile：
 outfile.write（infile.read（））
  

...另一个我想到的有趣的：

  filenames = ['file1.txt'，'file2.txt'，...] 
 with open（'path / to / output / file'，'w'）as outfile：
 for itertools.chain.from_iterable（itertools.imap（open，filnames））：
 outfile .write（line）
  

不幸的是，这最后一个方法留下了一些打开的文件描述符，无论如何照顾。我只是觉得这很有趣。

I have a list of 20 file names, like ['file1.txt', 'file2.txt', ...]. I want to write a Python script to concatenate these files into a new file. I could open each file by f = open(...), read line by line by calling f.readline(), and write each line into that new file. It doesn't seem very "elegant" to me, especially the part where I have to read//write line by line.

Is there a more "elegant" way to do this in Python?

解决方案

This should do it

For large files:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            for line in infile:
                outfile.write(line)

For small files:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            outfile.write(infile.read())

… and another interesting one that I thought of:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for line in itertools.chain.from_iterable(itertools.imap(open, filnames)):
        outfile.write(line)

Sadly, this last method leaves a few open file descriptors, which the GC should take care of anyway. I just thought it was interesting

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