如何在 Django 中让每五个帖子成为一个广告帖子 [英] How To Make Every Fifth Post An Ad Post In Django

问题描述

我试图让用户赞助一个帖子，以便为该帖子带来更多点击.我想每五个帖子发布一个赞助帖子，但如果我尝试在模板中使用可除数并循环浏览广告，那么它将在第四个帖子后发布所有广告

这是我试过的一些代码

我已将问题更改为不显示帖子的内容，有人可以告诉我我错在哪里吗?

型号:

类广告(models.Model):post = models.ForeignKey(发布，on_delete=models.CASCADE，null=True)

观看次数:

def home(request, pk):post_list = []广告列表 = []对于 Post.objects.all() 中的 p:post_list.append(p.Post)对于 Ads.objects.all() 中的 a:ad_list.append(p.Ads)n = 5iter1 = iter(post_list)post_ad_list = []对于 ad_list 中的 x:post_ad_list.extend([next(iter1) for _ in range(n - 1)])post_ad_list.append(x)post_ad_list.extend(iter1)上下文 = {帖子":post_ad_list，}返回渲染(请求，'new.html'，上下文)

我尝试过但不起作用的模板:

{% 用于帖子中的项目 %}//打印产品和广告{% 结束为 %}

解决方案

好的，这样你就可以枚举你的 Post 查询集，这样你就可以每 x 个对象插入一个广告.这将形成一种冗长且易于理解的方法.

或者你可以用 itertools 中的 chain 做一些类似这样的事情；

<预><代码>>>>N = 5 # 插入广告的元素>>>k = 'Ad' # 添加到列表中的东西>>>>>>list(chain(*[letters[i : i+N] + [k] if len(letters[i : i+N]) == N else 字母[i : i+N] for i in range(0, len(字母), N)]))['a', 'b', 'c', 'd', 'e', 'Ad', 'f', 'g', 'h', 'i', 'j', 'Ad', 'k', 'l']

如您所见，每 5 个元素添加一个广告".

如果将两个查询集转换为列表，则可以执行 ads.pop() 将元素插入到帖子列表中.

I am trying to allow users to sponsor a post to bring more clicks to there posts. I want to make every fifth post a post that is a sponsored post but if i try to just use divisible by in the templates and loop through ads then it will post all of the ads after the fourth post

here is some code i have tried

EDIT:I have changed the question to something that won't show the posts can someone show me where i'm wrong?

models:

class Ads(models.Model):
    post = models.ForeignKey(Post, on_delete=models.CASCADE, null=True)

views:

def home(request, pk):
    
   post_list = []
   ad_list = []
   for p in Post.objects.all():
       post_list.append(p.Post) 
   for a in Ads.objects.all():
       ad_list.append(p.Ads) 
   n = 5
   iter1 = iter(post_list)
   post_ad_list = []
   for x in ad_list:
       post_ad_list.extend([next(iter1) for _ in range(n - 1)])
       post_ad_list.append(x)
   post_ad_list.extend(iter1)

   context = {
       'posts': post_ad_list,
   }
return render(request, 'new.html', context)

templates i have tried but don't work:

{% for item in posts %}

    //prints products and ads

   
{% endfor %}

解决方案

Ok, so you could enumerate your Post queryset so that you can insert an ad every x objects. This would make for a verbose and easily understandable approach.

Or you could do something with chain from itertools a bit like this;

>>> N = 5  # element to insert ad
>>> k = 'Ad'  # Thing added to the list
>>>
>>> list(chain(*[letters[i : i+N] + [k] if len(letters[i : i+N]) == N else letters[i : i+N] for i in range(0, len(letters), N)]))
['a', 'b', 'c', 'd', 'e', 'Ad', 'f', 'g', 'h', 'i', 'j', 'Ad', 'k', 'l']

So as you can see there, an 'Ad' is added every 5 elements.

If you convert you two querysets into lists, you could do ads.pop() to insert the element into the list of posts.

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