R:如何计算列中以逗号分隔的所有字符值? [英] R: How to Count All Character Values Separated By Commas In A Column?
问题描述
下面是我正在使用的一些测试数据的几行.我想计算频率ICD10Code 列中由列分隔的所有字符.从片段下面的代码,我使用 group_by 因为每个PatientId"值在该列中都有重复但有其他列中的唯一值.如何计算所有字符值的频率?
Below is a couple of rows of some test data I am using. I am wanting to count the frequency of all the characters in the ICD10Code column which are separated by columns. From the segment of code below, I used group_by because every "PatientId" value had duplicates in that column but had unique values in other columns. How can I go about counting the frequency of all character values?
PatientId ReferralSource NextAppt Age InsuranceName ICD10Code
1584 St Francis Y 34 SLIDING FEE SCHEDULE M5136, N809, R51, Z6831
2655 Piedmont Hospital Y 60 Medicaid-GA (Medicaid) E119, E782, I10, L729, R809
结果如下所示.
M5136=1
N809=1
R51=1
作为 R 的新手,我尝试了在 Stack (sapply) 中找到的这段代码,并生成了一个每行特定行的总计数.
Being fairly new to R, I tried this segment of code found in Stack (sapply) and just produced a total count for each row specific row.
data.id <- data.1 %>% group_by(PatientId) %>%
summarise(ReferralSource=first(ReferralSource),NextAppt=first(NextAppt),
Age=max(Age),InsuranceName=toString(unique(InsuranceName)),
ICD10Code=toString(unique(ICD10Code)))
sapply(strsplit(data.id$ICD10Code,","),FUN=function(x){length(x[x!="Null"])})
这产生了每行的总数.
[1] 10 17 5 18 6 5 8 7 2 8 3 8 10 14 5 5 9 8 11 5 6 5 9 16 9 4 3 9 18 9 12
12 12 2 16 6 10
[38] 2 2 3 4 9 7 12 5 10 16 13 9 1 6 2 7 9 8 5 5 4 3 11 19 6 4 3 7 8 6
10 8 6 16 11 5 9
[75] 13 5 8 4 10 3 7 5 6 4 3 4 8 7 7 4 5 9 2 6 1 20 3 3 3 4 5 5 7 3
12 7 16 1 7 6 3
[112] 4 2 7 8 4 1 9 3 8 3 8 5 8 2 4 4 8 4 7 10 8 2 4 4 2 9 7 7 5 1
8 6 10 9 3 11 10
[149] 3 6 4 6 13 3 7 11 6 5 4 3 1 4 10 10 10 10 11 2 1 5 4 5 5 5 5 9 5 7
7 2 6 7 7 6 5
[186] 7 8 9
推荐答案
要统计ICD10Code
在整列中出现的频率,我们可以用逗号分割字符串,unlist
并用 table
计算.
To count the frequency of ICD10Code
in the entire column, we can split the string on comma, unlist
it and count it with table
.
table(unlist(strsplit(as.character(data.1$ICD10Code), ',')))
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