如何在 C++ 中创建 Lua 表，并将其传递给 Lua 函数? [英] How do I create a Lua Table in C++, and pass it to a Lua function?

问题描述

在 C++ 中，我有一个 map，其中包含未知数量的条目.如何将其传递给 Lua 函数，以便 Lua 函数可以将数据用作表?

In C++, I have a map<string, string>, containing an unknown number of entries. How can I pass this to a Lua function, so that the Lua function can use the data as a table?

推荐答案

如果你想要一个真正的lua表:

if you want a real lua table:

lua_newtable(L);
int top = lua_gettop(L);

for (std::map::iterator it = mymap.begin(); it != mymap.end(); ++it) {
    const char* key = it->first.c_str();
    const char* value = it->second.c_str();
    lua_pushlstring(L, key, it->first.size());
    lua_pushlstring(L, value, it->second.size());
    lua_settable(L, top);
}

用正确的地图类型替换...

with the right types for your map substituted in..

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