如何在基类上调用显式实现的接口方法 [英] How to call an explicitly implemented interface-method on the base class
问题描述
我有一种情况,两个类(一个派生自另一个)都显式地实现了相同的接口:
I have a situation, where two classes (one deriving from the other) both implement the same interface explicitly:
interface I
{
int M();
}
class A : I
{
int I.M() { return 1; }
}
class B : A, I
{
int I.M() { return 2; }
}
从I.M()
的派生类的实现,我想调用基类的实现,但我不知道怎么做.到目前为止我尝试的是这个(在 B 类中):
From the derived class' implementation of I.M()
, I'd like to call the implementation of the base class, but I don't see how to do it. What I tried so far is this (in class B):
int I.M() { return (base as I).M() + 2; }
// this gives a compile-time error
//error CS0175: Use of keyword 'base' is not valid in this context
int I.M() { return ((this as A) as I).M() + 2; }
// this results in an endless loop, since it calls B's implementation
有没有办法做到这一点,而不必实现另一个(非接口显式)辅助方法?
Is there a way to do this, without having to implement another (non interface-explicit) helper method?
更新:
我知道可以使用派生类可以调用的帮助程序"方法,例如:
I know it's possible with a "helper" method which can be called by the derived class, e.g:
class A : I
{
int I.M() { return M2(); }
protected int M2 { return 1; }
}
我也可以更改它以非显式地实现接口.但我只是想知道如果没有这些变通办法是否有可能.
I can also change it to implement the interface non-explicitly. But I was just wondering if it's possible without any of these workarounds.
推荐答案
不幸的是,这是不可能的.
甚至没有帮助方法.辅助方法与您的第二次尝试存在相同的问题:this
属于 B
类型,即使在基类中也会调用 M
的实现> 在 B
中:
Unfortunately, it isn't possible.
Not even with a helper method. The helper method has the same problems as your second attempt: this
is of type B
, even in the base class and will call the implementation of M
in B
:
interface I
{
int M();
}
class A : I
{
int I.M() { return 1; }
protected int CallM() { return (this as I).M(); }
}
class B : A, I
{
int I.M() { return CallM(); }
}
唯一的解决方法是在 A
的 M
实现中使用的 A
中的辅助方法:
The only workaround would be a helper method in A
that is used in A
's implementation of M
:
interface I
{
int M();
}
class A : I
{
int I.M() { return CallM(); }
protected int CallM() { return 1; }
}
class B : A, I
{
int I.M() { return CallM(); }
}
但是如果有一个 class C : B, I
...
But you would need to provide a method like this also for B
if there will be a class C : B, I
...
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