无法访问派生模板类中模板基类的成员 [英] Can't access members of a Template base class within a derived template class
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问题描述
我有一个模板基类.可以说.
I have a template base class.Lets say.
template<class KeyF>
class Base
{
private:
int member1;
char member2;
....
};
我从上面的类派生了另一个类.
I derived another class from above class.
template<class KeyF>
class Derived : public Base<KeyF>
{
public:
void func1() {
<accessing member1/member2>
}
....
};
以上代码无法在 gcc 中编译.说 member1 不是 Derived 的成员.但是已经是从一个Base Class派生出来的,那为什么不能访问它的成员呢?
Above code doesn't compile in gcc. saying that member1 is not a member of Derived. But it is already derived from a Base Class, then why can't it access its member?
推荐答案
Base
中的成员是 private
.您不能访问该类之外的类的私有成员
(friend
除外).使它们protected
,或protected getter
.
Members in Base
are private
. You cannot access private members
of class, outside of this class (except friend
). Make them protected
, or make protected getters
.
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