如何从 request.FILES 获取文件名? [英] How can I get the file name from request.FILES?
本文介绍了如何从 request.FILES 获取文件名?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何从 Django 中的 request.FILES 获取文件名?
How can I get the file name from request.FILES in Django?
def upload(request):
if request.method == 'POST':
form = UploadForm(request.POST, request.FILES)
if form.is_valid():
upload = Upload()
upload.timestamp = datetime.datetime.now()
save_instance(form, upload)
我试过用这个,但没有用:
I tried using this but it did not work:
if 'filename' in request.FILES:
filename = request.FILES['filename']
推荐答案
request.FILES['filename'].name
来自request
文档.
如果您不知道密钥,您可以遍历文件:
If you don't know the key, you can iterate over the files:
for filename, file in request.FILES.iteritems():
name = request.FILES[filename].name
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