我如何从request.FILES获取文件名？ [英] How can i get the file name from request.FILES?

问题描述

如何从Django中的request.FILES获取文件名？

How can I get the file name from request.FILES in Django?

def upload(request):
    if request.method == 'POST':
        form = UploadForm(request.POST, request.FILES)
        if form.is_valid():
            upload = Upload()
            upload.timestamp = datetime.datetime.now()
            save_instance(form, upload)

我尝试使用这个但没有起作用：

I tried using this but it did not work:

  if 'filename'  in request.FILES:
         filename = request.FILES['filename']

推荐答案

request.FILES['filename'].name

从 请求 文档。

如果您不知道密钥，可以遍历文件：

If you don't know the key, you can iterate over the files:

for filename, file in request.FILES.iteritems():
    name = request.FILES[filename].name

这篇关于我如何从request.FILES获取文件名？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！