在队列<byte[]>中记录语音并将其发送到服务器 [英] record voice in a Queue<byte[]> and send it to the server
问题描述
我正在开发语音应用程序.
I am developing voice application.
我需要某种缓冲区队列,以便我在线程中连续记录,将充满字节的缓冲区放入队列并传输到服务器,然后从队列中取出下一个缓冲区.
I need a buffer queue of some sort so that i record continuosly in a thread , place the buffers full of bytes into the queue and to transmit to the server, and i take the next buffer from the queue.
这是录音代码:
Queue<byte[]> qArray = new LinkedList<byte[]>();
recordingThread = new Thread(new Runnable() {
@Override
public void run() {
bData = new byte[BufferElements];
while (isRecording) {
recorder.read(bData, 0, BufferElements);
qArray.add(bData);
if (AudioRecord.ERROR_INVALID_OPERATION != 0) {
SendAudio();
}
}
}
}, "AudioRecorder Thread");
recordingThread.start();
但是在将它发送到服务器时仍然缺少一些 byte[] 数据
这里是发送语音到服务器的代码:
Here is the sending voice to the server code:
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(ServerUrl.url_audio);
// Json Format
JSONObject holder = new JSONObject();
JSONArray jArray = new JSONArray();
try {
byte[] tmparr = qArray.poll();
for (int i = 0; i < tmparr.length; i++) {
jArray.put(i, tmparr[i]);
}
holder.put("Voice", jArray);
我不想错过任何正在记录的数据.
I dont want to miss any data which is recording.
任何帮助将不胜感激.谢谢
Any help would be appreciated lot. Thanks
推荐答案
当你将一个 byte[] 放入队列时,你需要创建一个新的缓冲区.否则下一个记录将覆盖相同的缓冲区.只需将 bData
的初始化移动到循环中即可:
When you place a byte[] into the queue, you need to then create a new buffer. Otherwise the next recording will overwrite the same buffer. Just move the initialization of bData
into the loop:
Queue<byte[]> qArray = new LinkedList<byte[]>();
recordingThread = new Thread(new Runnable() {
@Override
public void run() {
while (isRecording) {
bData = new byte[BufferElements];
recorder.read(bData, 0, BufferElements);
qArray.add(bData);
if (AudioRecord.ERROR_INVALID_OPERATION != 0) {
SendAudio();
}
}
}
}, "AudioRecorder Thread");
recordingThread.start();
您还应该添加逻辑来限制队列的大小.如果队列溢出,您仍然会丢失数据,但至少不会因内存不足错误而崩溃.
You should also add logic to limit the size of the queue. If the queue overflows, you will still lose data, but at least you won't crash with an out-of-memory error.
EDIT 这是记录循环的修改版本,可以进行正确的错误检查.它使用 Queue
而不是 Queue
:
EDIT Here's a modified version of the recording loop that does proper error checking. It uses a Queue<ByteBuffer>
instead of a Queue<byte[]>
:
public void run() {
bData = ByteBuffer.allocate(BufferElements);
while (isRecording && !isInterrupted()) {
int result = recorder.read(bData, 0, BufferElements);
if (result > 0) {
qArray.add(bData);
SendAudio();
bData = ByteBuffer.allocate(BufferElements);
} else if (result == AudioRecord.ERROR_INVALID_OPERATION) {
Log.e("Recording", "Invalid operation error");
break;
} else if (result == AudioRecord.ERROR_BAD_VALUE) {
Log.e("Recording", "Bad value error");
break;
} else if (result == AudioRecord.ERROR) {
Log.e("Recording", "Unknown error");
break;
}
try {
Thread.sleep(50);
} catch (InterruptedException e) {
break;
}
}
}
当然,您需要在某个地方调用 recorder.startRecording()
否则您将无法获得任何数据.
Of course, somewhere you'll need to call recorder.startRecording()
or you won't get any data.
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