TypeScript 模块增强 [英] TypeScript module Augmentation

问题描述

我有可观察的扩展.它工作得很好，但现在我已经用 typescript 2.7.2 更新到了 angular 6.

I have extension for observable. It was working perfectly fine but now I've updated to angular 6 with typescript 2.7.2.

import { Observable } from 'rxjs/Observable';
import { BaseComponent } from './base-component';
import { Subscription } from 'rxjs/Subscription';
import { Subscribable } from 'rxjs';

declare module 'rxjs/Observable' {
    export interface Observable<T> {
        safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
            next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription;
    }
}


export function safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
    next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription {
    let sub = this.subscribe(next, error, complete);
    component.markForSafeDelete(sub);
    return sub;
}

Observable.prototype.safeSubscribe = safeSubscribe;

此代码不起作用

1. 'Observable' 仅指一种类型，但在此处用作值.
2. Observable"类型不存在subscribe"属性.

https://www.typescriptlang.org/docs/handbook/declaration-合并.html

推荐答案

合并声明时，指定的模块路径必须与实际模块的路径完全匹配.

When merging declarations, the specified module path must exactly match the path to the actual module.

使用 RxJS 版本 6，您将需要更改模块声明，因为内部结构已更改.凭记忆，应该是:

With RxJS version 6, you will need to change your module declaration, as the internal structure has changed. From memory, it should be:

declare module 'rxjs/internal/Observable' {
    export interface Observable<T> {
        safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
            next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription;
    }
}

例如，请参阅其中一个在 rxjs-compat 中修补导入.

For an example, see one of the patching imports in rxjs-compat.

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