如何强制在 WebView 中单击的任何链接在 Safari 中打开? [英] How can I force any links clicked within a WebView to open in Safari?

问题描述

我的应用程序中有一个 WebView，我希望在 WebView 中单击的任何链接在 Safari 中打开(而不是 WebView 本身).

I have a WebView in my application and I would like any links clicked within the WebView to open in Safari (instead of the WebView itself).

我正在 Swift 中开发应用程序.

I am developing the application in Swift.

这样做的最佳方法是什么?

What is the best method to do this?

推荐答案

这在 Swift 中的完成方式与在 Obj-C 中的基本相同:

This is done essentially the same way in Swift as in Obj-C:

首先声明你的视图控制器符合UIWebViewDelegate

First, declare that your view controller conforms to UIWebViewDelegate

class MyViewController: UIWebViewDelegate

然后实现webViewShouldStartLoadingWithRequest:navigationType: 在你的视图控制器中:

Then implement webViewShouldStartLoadingWithRequest:navigationType: in your View Controller:

// Swift 1 & 2
func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .LinkClicked:
        // Open links in Safari
        UIApplication.sharedApplication().openURL(request.URL)
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

// Swift 3
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .linkClicked:
        // Open links in Safari
        guard let url = request.url else { return true }

        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url, options: [:], completionHandler: nil)
        } else {
            // openURL(_:) is deprecated in iOS 10+.
            UIApplication.shared.openURL(url)
        }
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

最后，设置您的 UIWebView 的委托，例如，在 viewDidLoad 或您的 Storyboard 中:

Finally, set your UIWebView's delegate, e.g., in viewDidLoad or in your Storyboard:

webView.delegate = self

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