如何在Xcode中的safari中打开webview中的任何链接？ [英] How can I make any links within a webview open in safari in Xcode?

问题描述

我的应用程序中有一个webview，我希望Web视图中的任何链接都可以在safari中打开，而不是在Web视图中打开。

I have a webview in my application and I would like any links in the web view to open in safari instead of the web view itself.

我正在编码应用程序在swift中，并且已经看到了objective-c的一些答案，但没有看到swift的答案。

I am coding the application in swift, and have seen some answers for objective-c but none for swift.

有人知道我该怎么做吗？

Does anybody know how I can go about doing this?

推荐答案

这在Swift和Obj-C中完全相同：

This is done essentially the same way in Swift as in Obj-C:

首先，声明你的视图控制器符合 UIWebViewDelegate

First, declare that your view controller conforms to UIWebViewDelegate

class MyViewController: UIWebViewDelegate

然后实施 webViewShouldStartLoadingWithRequest：navigationType： ：

// Swift 1 & 2
func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .LinkClicked:
        // Open links in Safari
        UIApplication.sharedApplication().openURL(request.URL)
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

// Swift 3
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .linkClicked:
        // Open links in Safari
        guard let url = request.url else { return true }

        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url, options: [:], completionHandler: nil)
        } else {
            // openURL(_:) is deprecated in iOS 10+.
            UIApplication.shared.openURL(url)
        }
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

最后，设置 UIWebView 的委托，例如，在 viewDidLoad 或在你的故事板中：

Finally, set your UIWebView's delegate, e.g., in viewDidLoad or in your Storyboard:

webView.delegate = self

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