如何在Safari中打开网址而不是在webview中 [英] how to open the url in safari not in webview
问题描述
我想在safari中打开一个网址，超出应用程序，而不是在webview中。
I want to open an url in safari, outisde the app and not in webview.
我实现了 UIWebViewDelegate 但我仍然无法打开网址。
基本上我无法点击网址。
I implemented the UIWebViewDelegate but I am still not able to open the url. Basically I am not able to click the url.
以下是代码：
-(void)newView:(NSString *)title Description:(NSString *)desc URL:(NSString *)url{
webView =[[UIWebView alloc]initWithFrame:CGRectMake(15, 17, 190, 190)];
webView.backgroundColor=[UIColor clearColor];
webView.delegate=self;
webView.opaque = NO;
[webView loadHTMLString:[NSString stringWithFormat:@"<html><body p style='color:white' text=\"#FFFFFF\" face=\"Bookman Old Style, Book Antiqua, Garamond\" size=\"5\">%@ %@</body></html>", desc,url] baseURL:nil];
v = [[HUDView alloc] initWithFrame:CGRectMake(60, 70, 220, 220)];
cancelButton = [UIButton buttonWithType:UIButtonTypeCustom];
cancelButton.frame = CGRectMake(0, 0, 30, 30);
[cancelButton setBackgroundImage:[UIImage imageNamed:@"closebox.png"] forState:UIControlStateNormal];
[cancelButton addTarget:self action:@selector(cancelButtonPressed) forControlEvents:UIControlEventTouchUpInside];
[v addSubview:cancelButton];
[v addSubview:webView];
[self.view addSubview:v];
}
-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
if ( inType == UIWebViewNavigationTypeLinkClicked ) {
[[UIApplication sharedApplication] openURL:[inRequest URL]];
return NO;
}
return YES;
}
推荐答案
阅读评论之后我认为这就是你要找的东西：
After reading the comments I think this is what you're looking for:
实现这个方法：
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType;
来自 UIWebViewDelegate 并取决于该请求参数你应该返回 TRUE 或 FALSE 。如果您不希望Web视图打开它，您应该致电：
from UIWebViewDelegate and depending on that request argument you should return TRUE or FALSE. If you don't want the web view to open it, you should call:
[[UIApplication sharedApplication] openURL:request.URL];
正如其他人提到的那样并返回 FALSE 。
as others mentioned and return FALSE.
希望这会有所帮助。干杯！
Hope this helps. Cheers!
编辑：如果您的网络视图中无法识别链接，请尝试以下操作：
If the links are not recognized in your web view, try this:
[webView setDataDetectorTypes:UIDataDetectorTypeLink]
这篇关于如何在Safari中打开网址而不是在webview中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
