Django Order_BY 自定义函数 [英] Django Order_BY custom function
问题描述
我在模型 roll_numb
中有字段.roll_numb
的值如下.
I have field in model roll_numb
. Theroll_numb
has values as follows.
070-001
070-007
070-343
080-002
080-008
当我 order_by
roll_numb
时,排序和上面一样.我想按 -
拆分 roll_numb 并按余数排序.(即 001、002、008)
When i order_by
roll_numb
the sorting is as it is above.
I want to split the roll_numb by -
and sort by the remainder. (i.e. 001, 002, 008)
class Meta:
ordering = ['roll_numb']
推荐答案
我认为不可能在 Django 的 ORM 范围内通过 model
的方法来订购 queryset
.
I think it is not possible to order a queryset
by method of model
in Django's ORM scope.
因此,为了通过您的自定义方法对您的 queryset
进行排序,我推荐两种方法:
So in order to sort your queryset
by your custom method, I recommend 2 ways:
第一
qs = mymodel.objects.all()
qs = sorted(qs, key: lambda i: i.roll_numb().split('-')[1])
第二
向您的模型添加另一个字段,以便启用 Django 的 ORM 以按所需值排序:
Add another field to your model, so enable Django's ORM to sort by the desired value:
MyModel(models.Model):
class Meta:
ordering = ['roll_numb_splitted']
roll_numb_splitted = models.Charfield(max_length=3)
def save(self, *args, **kwargs):
# this is a check to run once
if not self.pk:
self.roll_numb_splitted = self.roll_numb().split('-')[1]
return super(MyModel, self).save(*args, **kwargs)
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