测试 Python 中是否存在可执行文件? [英] Test if executable exists in Python?
问题描述
在 Python 中,是否有一种可移植且简单的方法来测试可执行程序是否存在?
In Python, is there a portable and simple way to test if an executable program exists?
简单来说,我的意思是类似于 which
命令,它会是完美的.我不想手动搜索 PATH 或涉及尝试使用 Popen
& 执行它的事情.看看它是否失败(这就是我现在正在做的,但想象一下它是 launchmissiles
)
By simple I mean something like the which
command which would be just perfect. I don't want to search PATH manually or something involving trying to execute it with Popen
& al and see if it fails (that's what I'm doing now, but imagine it's launchmissiles
)
推荐答案
我能想到的最简单的方法:
Easiest way I can think of:
def which(program):
import os
def is_exe(fpath):
return os.path.isfile(fpath) and os.access(fpath, os.X_OK)
fpath, fname = os.path.split(program)
if fpath:
if is_exe(program):
return program
else:
for path in os.environ["PATH"].split(os.pathsep):
exe_file = os.path.join(path, program)
if is_exe(exe_file):
return exe_file
return None
编辑:更新了代码示例以包含用于处理所提供参数已经是可执行文件的完整路径(即which/bin/ls")的情况的逻辑.这模仿了 UNIX 'which' 命令的行为.
Edit: Updated code sample to include logic for handling case where provided argument is already a full path to the executable, i.e. "which /bin/ls". This mimics the behavior of the UNIX 'which' command.
编辑:更新为使用 os.path.isfile() 而不是 os.path.exists() 每条评论.
Edit: Updated to use os.path.isfile() instead of os.path.exists() per comments.
编辑:path.strip('"')
在这里似乎是错误的做法.Windows 和 POSIX 似乎都不鼓励引用 PATH 项.
Edit: path.strip('"')
seems like the wrong thing to do here. Neither Windows nor POSIX appear to encourage quoted PATH items.
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