Clojure:半展平嵌套序列 [英] Clojure: Semi-Flattening a nested Sequence

问题描述

我有一个嵌入向量列表的列表，它看起来像:

I have a list with embedded lists of vectors, which looks like:

(([1 2]) ([3 4] [5 6]) ([7 8]))

我知道与之合作并不理想.我想将其展平为 ([1 2] [3 4] [5 6] [7 8]).

Which I know is not ideal to work with. I'd like to flatten this to ([1 2] [3 4] [5 6] [7 8]).

flatten 不起作用:它给了我 (1 2 3 4 5 6 7 8).

flatten doesn't work: it gives me (1 2 3 4 5 6 7 8).

我该怎么做?我想我需要根据每个列表项的 contents 创建一个新列表，而不是项目，这是我无法从文档中找到如何做的部分.

How do I do this? I figure I need to create a new list based on the contents of each list item, not the items, and it's this part I can't find out how to do from the docs.

推荐答案

如果你只想把它扁平化一级，你可以使用 concat

If you only want to flatten it one level you can use concat

(apply concat '(([1 2]) ([3 4] [5 6]) ([7 8])))
=> ([1 2] [3 4] [5 6] [7 8])

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