Clojure：半平化嵌套序列 [英] Clojure: Semi-Flattening a nested Sequence

问题描述

我有一个包含向量嵌入列表的列表，如下所示：

I have a list with embedded lists of vectors, which looks like:

（（[1 2]）（[3 4] [5 6]）（[7 8]））

我知道是不理想的。我想把它变成（[1 2] [3 4] [5 6] [7 8]）。

Which I know is not ideal to work with. I'd like to flatten this to ([1 2] [3 4] [5 6] [7 8]).

flatten不工作：它给我（1 2 3 4 5 6 7 8）。

flatten doesn't work: it gives me (1 2 3 4 5 6 7 8).

我该如何做？我想我需要基于每个列表项目的内容创建一个新的列表，而不是项目，这是我从文档中找不到如何做。

How do I do this? I figure I need to create a new list based on the contents of each list item, not the items, and it's this part I can't find out how to do from the docs.

推荐答案

如果你只想将它展平一级，你可以使用 concat

If you only want to flatten it one level you can use concat

(apply concat '(([1 2]) ([3 4] [5 6]) ([7 8])))
=> ([1 2] [3 4] [5 6] [7 8])

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