Clojure- 在函数内部定义变量? [英] Clojure- Defining a variable inside of a function?

查看:22
本文介绍了Clojure- 在函数内部定义变量?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这个变量,hand,当我自己定义它时效果很好.

I have this variable, hand, that works just fine when I define it on its own.

(def yourHand
(map
 ;;fn
 #(let [x %]
       (cond
         ;;hearts
         (< x 10) (* x -1)
         (< x 13) -10
         ;;diamonds
         (< x 23) (* (mod x 13) -1)
         (< x 26) -10
         ;;clubs
         (< x 36) (mod x 13)
         (< x 39) 10
         ;;spades
         (< x 49) (mod x 13)
         (< x 52) 10
         ))
 ;;list
 (take (rand-int 12) (repeatedly #(+ 1 (rand-int 52))))))

我想在此函数中使用此变量.当我先定义变量然后在函数中使用它的名称时,这很好用.

I would like to use this variable in this function here. This works just fine when I define the variable first then just use its name in the function.

(reduce + (vec (map #(let [x %]
                      (cond
                        (= x 1) 1
                        :else 0
                        ))
                yourHand)))

当我尝试在函数中定义变量时,问题就出现了,就像这样.

The issue arrises when I try to define the variable within the function, like this.

(reduce + (vec (map #(let [x %]
                      (cond
                        (= x 1) 1
                        :else 0
                        ))
                (def hand
                  (map
                    ;;fn
                    #(let [x %]
                          (cond
                            ;;hearts
                            (< x 10) (* x -1)
                            (< x 13) -10
                            ;;diamonds
                            (< x 23) (* (mod x 13) -1)
                            (< x 26) -10
                            ;;clubs
                            (< x 36) (mod x 13)
                            (< x 39) 10
                            ;;spades
                            (< x 49) (mod x 13)
                            (< x 52) 10
                            ))
                    ;;list
                    (take (rand-int 12) (repeatedly #(+ 1 (rand-int 52)))))))))

如果不是两件事,这将是不必要的.首先,如果可能的话,我想把这个程序压缩成一个函数(我认为它/是/可能的!).其次,我需要在我的程序的另一个点使用这个变量,所以我需要能够以某种方式引用它.

This would not be necessary if not for 2 things. First, I would like to condense this program down to one function if possible (and I think it /is/ possible!). Second, I need to use this variable at another point in my program so I need to be able to reference it somehow.

无论如何,当我尝试评估上述函数时,它抱怨它不知道如何从:clojure.lang.Var 创建 ISeq".(这是错误:IllegalArgumentException 不知道如何从以下位置创建 ISeq:clojure.lang.Var clojure.lang.RT.seqFrom (RT.java:542))我假设这意味着它不知道如何将我的变量用作向量......但是当我在函数之外定义我的变量时,它似乎可以将它用作向量!

Anyway, when I try to evaluate the above function, it complains that it doesn't know "how to create ISeq from: clojure.lang.Var". (This is the error: IllegalArgumentException Don't know how to create ISeq from: clojure.lang.Var clojure.lang.RT.seqFrom (RT.java:542)) I'm assuming this means that it doesn't know how to use my variable as a vector... but it seems to use it as a vector just fine when I define my variable outside of the function!

有什么建议吗?

推荐答案

你不应该尝试在函数内部def.通常 def 用于顶级命名空间值;加载命名空间后(通常)不会改变的东西.

You shouldn't try to def inside of functions. Generally defs are for top-level namespace values; things that won't (normally) change after the namespace is loaded.

让我们稍微重构一下代码以获得一些不依赖于顶级/静态命名空间值的可重用函数.代替 (def yourHand ...) 我们可以有一个生成 hands 的函数:

Let's refactor the code a bit to get some reusable functions that don't depend on top-level/static namespace values. Instead of (def yourHand ...) we can have a function that generates hands:

(defn deal-hand []
  (map
    ;;fn
    #(cond ;; you have a subtle bug here that sometimes returns nil
       ;;hearts
       (< % 10) (* % -1)
       (< % 13) -10
       ;;diamonds
       (< % 23) (* (mod % 13) -1)
       (< % 26) -10
       ;;clubs
       (< % 36) (mod % 13)
       (< % 39) 10
       ;;spades
       (< % 49) (mod % 13)
       (< % 52) 10)
    ;;list
    (take (rand-int 12) (repeatedly #(inc (rand-int 52))))))

如果你还想要一个命名空间def,你可以这样得到:

Then if you still wanted a namespace def, you could get it like this:

(def your-hand (deal-hand))

而且我们可以将您的 reduce 包装在另一个帮助的函数中:

And we can wrap your reduce in another function that takes a hand:

(defn score-hand [hand] ;; I made a few simplifications here, but logic is the same
  (reduce + (mapv #(if (= 1 %) 1 0) hand)))

现在您有两个可重复使用的函数,可以生成和得分手:

Now you have two reusable functions that can generate and score hands:

(deal-hand)
=> (-10 -9 -9 -10 -3 7)
(deal-hand)
=> (8 -2 10 -9 1 2 -10 3 nil 5)
(score-hand (deal-hand))
=> 1

如果您需要在程序的其他部分使用手,请考虑如何构建函数以将手作为输入,以及手如何在程序的函数中流动.

If you need to use a hand in other parts of your program, think about how you can structure your functions to take hands as input, and how hands can flow through your program's functions.

这篇关于Clojure- 在函数内部定义变量?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆