在python中修改内部函数的函数变量 [英] Modify the function variables from inner function in python

问题描述

可以打印外部函数变量 a

It's ok to get and print the outer function variable a

def outer():
    a = 1
    def inner():
        print a

也可以获得外部函数数组 a 并附加一些内容

It's also ok to get the outer function array a and append something

def outer():
    a = []
    def inner():
        a.append(1)
        print a

然而，当我尝试增加整数时会引起一些麻烦：

However, it caused some trouble when I tried to increase the integer:

def outer():
    a = 1
    def inner():
        a += 1 #or a = a + 1
        print a

>> UnboundLocalError: local variable 'a' referenced before assignment

为什么会发生这种情况，我该如何实现我的目标（增加整数）？

Why does this happen and how can I achieve my goal (increase the integer)?

推荐答案

Python 2的解决方法：

Workaround for Python 2:

def outer():
    a = [1]
    def inner():
        a[0] += 1
        print a[0]

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