从python内部函数修改函数变量 [英] Modify the function variables from inner function in python

问题描述

获取并打印外层函数变量a

It's ok to get and print the outer function variable a

def outer():
    a = 1
    def inner():
        print a

获取外层函数数组a并追加一些东西也可以

It's also ok to get the outer function array a and append something

def outer():
    a = []
    def inner():
        a.append(1)
        print a

然而，当我尝试增加整数时，它引起了一些麻烦:

However, it caused some trouble when I tried to increase the integer:

def outer():
    a = 1
    def inner():
        a += 1 #or a = a + 1
        print a

>> UnboundLocalError: local variable 'a' referenced before assignment

为什么会发生这种情况，我该如何实现我的目标(增加整数)?

Why does this happen and how can I achieve my goal (increase the integer)?

推荐答案

Python 2 的解决方法:

Workaround for Python 2:

def outer():
    a = [1]
    def inner():
        a[0] += 1
        print a[0]

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