使用委托和协议在 2 UIViewController 之间传递数据 [英] Passing data between 2 UIViewController using delegate and protocol

问题描述

我知道这个问题在这里已经被问过和回答过很多次了.但是我是第一次处理这个事情，仍然无法在我的脑海中得到完美的实现.这是我实现的委托方法的代码，用于将数据从 SecondViewController 传递到 FirstViewController.

I know this question has been asked and answered many times over here. But I am dealing with this thing for the first time and still not able to get the perfect implementation of it in my mind. Here's the code I have the delegate method I implement to pass data from SecondViewController to FirstViewController.

FirstViewController.h

#import "SecondViewController.h"

@interface FirstViewController : UITableViewController<sampleDelegate> 
@end

FirstViewController.m

@interface FirstViewController ()

// Array in which I want to store the data I get back from SecondViewController.
@property (nonatomic, copy) NSArray *sampleData;
@end

@implementation FirstViewController
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
   SecondViewController *controller = [[SecondViewController alloc] init];          
   [self.navigationController pushViewController:controller animated:YES];
}
@end

SecondViewController.h

@protocol sampleDelegate <NSObject>
- (NSArray*)sendDataBackToFirstController;
@end

@interface SecondViewController : UITableViewController
@property (nonatomic, strong) id <sampleDelegate> sampleDelegateObject;
@end

SecondViewController.m

@interface SecondViewController ()
@property (strong, nonatomic) NSArray *dataInSecondViewController;
@end

@implementation SecondViewController

- (void)viewDidLoad
{
    [super viewDidLoad];
    self.dataInSecondViewController = [NSArray arrayWithObjects:@"Object1", @"Object2", nil];
}

- (NSArray*)sendDataBackToFirstController
{
    return self.dataInSecondViewController;
}
@end

我做对了吗?我只希望它将 self.dataInSecondViewController 中的数据发送到 FirstViewController 并将其存储在 NSArray 属性中 sampleDataFirstViewController 的代码>.

Am I doing it correctly? All I want it to send the data in self.dataInSecondViewController to FirstViewController and store it over there in the NSArray property sampleData of FirstViewController.

不知何故，我无法访问 FirstViewController 中的 sendDataBackToFirstController.我在访问 sendDataBackToFirstController 时还缺少哪些其他东西?

Somehow I am not able to access sendDataBackToFirstController in FirstViewController. What other things I am missing implementing to access sendDataBackToFirstController there?

推荐答案

不太对.首先，您需要在第一个视图控制器中分配委托属性，以便第二个视图控制器知道要向哪个对象发送消息.

Not quite right. First you need to assign the delegate property in the first view controller so the second view controller knows which object to send messages to.

FirstViewController.m

FirstViewController.m

controller.delegate = self;

其次，您可以向后发送和接收委托方法.您设置的方式是 FirstViewController 应该在第二个控制器上调用 sendDataBackToFirstController.在委托模式中，SecondViewController 是发送消息并可选地使用该方法发送数据的那个.因此，您应该将委托声明更改为如下所示:

Second, you have the sending and receiving of your delegate method backwards. You have it setup in a way where the FirstViewController is expected to call sendDataBackToFirstController on the second controller. In a delegate pattern, the SecondViewController is the one that sends the message and optionally sends data with that method. So, you should change your delegate declaration to something like this:

@protocol sampleDelegate <NSObject>
- (void)secondControllerFinishedWithItems:(NSArray* )newData;
@end

然后，当您的 SecondViewController 完成其任务并需要通知其委托时，它应该执行以下操作:

Then, when your SecondViewController finishes its tasks and needs to notify its delegate, it should do something like this:

// ... do a bunch of tasks ...
// notify delegate
if ([self.delegate respondsToSelector:@selector(secondControllerFinishedWithItems:)]) {
    [self.delegate secondControllerFinishedWithItems:arrayOfNewData];
}

我在这里添加了一个额外的 if 语句来检查以确保委托在实际发送之前会响应我们想要发送的方法.如果我们的协议中有可选方法而没有这个，应用就会崩溃.

I added an extra if statement here to check to make sure the delegate will respond to the method we want to send it before actually sending it. If we had optional methods in our protocol and did not have this, the app would crash.

希望这有帮助！

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