Flask Button 在不刷新页面的情况下运行 Python? [英] Flask Button run Python without refreshing page?

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问题描述

我刚刚开始使用 python 和烧瓶(用于树莓派).我想要一个 Web 应用程序,它可以执行一些 Python 代码来平移和倾斜相机并显示视频流.

I am just getting started into python and flask (for the raspberry pi). I want a web application that would execute some python code to pan and tilt a camera and display a video stream.

到目前为止,我的烧瓶代码是:

My code up until now for flask is:

from flask import Flask, render_template
import time
import serial
#ser = serial.Serial('/dev/ttyUSB0',9600)
app = Flask(__name__)
@app.route('/')
@app.route('/<cmd>') #each button in my html redirects to a specified directory
def execute(cmd=None):
    if cmd == "down":
        print "Moving Down"
        #ser.write("D")

    if cmd == "up":
        print "Moving Up"
        #ser.write("U")

    if cmd == "left":
        print "Moving Left"
        # ser.write("L")

    if cmd == "right":
        print "Moving Right"
        #ser.write("R")

    if cmd == "reset":
        print "Reseting.."
        #ser.write("X")

    return render_template("main.html")


if __name__ == "__main__":
    app.run(host='0.0.0.0', port=8080, debug=True)

问题是我的代码依赖于每个按钮重定向到一个新目录,虽然这很好用,但它每次都会刷新页面,这意味着我的嵌入视频会再次重新加载和缓冲.有没有更好的方法来检测按钮按下然后使用flask执行python代码?

The problem is my code relies on the each button redirecting to a new directory, while this does work well, it refreshes the page each time which means my embedded video reloads and buffers again. Is there a better way of detecting a button press and then executing python code using flask?

推荐答案

我会把它分成两条路线,以便更容易地看到你必须做什么:

I would split it out into two routes to make it easier to see what you have to do:

LEFT, RIGHT, UP, DOWN, RESET = "left", "right", "up", "down", "reset"
AVAILABLE_COMMANDS = {
    'Left': LEFT,
    'Right': RIGHT,
    'Up': UP,
    'Down': DOWN,
    'Reset': RESET
}

@app.route('/')
def execute():
    return render_template('main.html', commands=AVAILABLE_COMMANDS)

@app.route('/<cmd>')
def command(cmd=None):
    if cmd == RESET:
       camera_command = "X"
       response = "Resetting ..."
    else:
        camera_command = cmd[0].upper()
        response = "Moving {}".format(cmd.capitalize())

    # ser.write(camera_command)
    return response, 200, {'Content-Type': 'text/plain'}

然后在你的模板中你只需要使用一些 JavaScript 来发送请求:

Then in your template you just need to use some JavaScript to send off the request:

{# in main.html #}
{% for label, command in commands.items() %}
    <button class="command command-{{ command }}" value="{{ command }}">
        {{ label }}
    </button>
{% endfor %}

{# and then elsewhere #}
<script>
// Only run what comes next *after* the page has loaded
addEventListener("DOMContentLoaded", function() {
  // Grab all of the elements with a class of command
  // (which all of the buttons we just created have)
  var commandButtons = document.querySelectorAll(".command");
  for (var i=0, l=commandButtons.length; i<l; i++) {
    var button = commandButtons[i];
    // For each button, listen for the "click" event
    button.addEventListener("click", function(e) {
      // When a click happens, stop the button
      // from submitting our form (if we have one)
      e.preventDefault();

      var clickedButton = e.target;
      var command = clickedButton.value;

      // Now we need to send the data to our server
      // without reloading the page - this is the domain of
      // AJAX (Asynchronous JavaScript And XML)
      // We will create a new request object
      // and set up a handler for the response
      var request = new XMLHttpRequest();
      request.onload = function() {
          // We could do more interesting things with the response
          // or, we could ignore it entirely
          alert(request.responseText);
      };
      // We point the request at the appropriate command
      request.open("GET", "/" + command, true);
      // and then we send it off
      request.send();
    });
  }
}, true);
</script>

这篇关于Flask Button 在不刷新页面的情况下运行 Python?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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