使用 Linq To XML，获取所有叶子路径的方法? [英] Using Linq To XML, method to get path to all leaves?

问题描述

好的，我有以下 XML 树

Ok, I've got the following XML tree

<root>
    <A>
        <A1>
            <A1A>1000</A1A>
            <A1B>2000</A1B>
            <A1C>3000</A1C>
        </A1>
        <A2>
            <A2A>4000</A2A>
            <A2B>5000</A2B>
        </A2>
    </A>
    <B>
        <B1>
            <B1A>6000</B1A>
        </B1>
    </B>
</root>

从接收 XDocument 的方法中，我想生成一个字典，其中键是路径(实际上是 XPath)，值来自相应叶中的值.

From a method receiving an XDocument I want to produce a dictionary where the key is the path (really an XPath) and the value comes from the value in the corresponding leaf.

root/A/A1/A1A    1000
root/A/A1/A1B    2000
root/A/A1/A1C    3000
root/A/A2/A2A    4000
root/A/A2/A2B    5000
root/B/B1/B1A    6000

在 Linq to XML 中做起来似乎很简单，但我无法理解它.

Seems simple to do in Linq to XML but I can't wrap my head around it.

推荐答案

您可以通过查找没有后代的元素来找到叶子:

You can find the leaves by looking for elements that have no descendants:

var doc = XDocument.Load(fileName);
var leaves = 
    from e in doc.Descendants()
    where !e.Elements().Any()
    select e;

我不知道有没有内置的方法来获取元素的路径，但是你可以很容易地创建一个扩展方法来构建它:

I don't know if there is a built-in way to get the path of an element, but you can easily create an extension method to build it:

static class Extensions
{
    public static string Path(this XElement element)
    {
        XElement tmp = element;
        string path = string.Empty;
        while (tmp != null)
        {
            path = "/" + tmp.Name + path;
            tmp = tmp.Parent;
        }
        return path;
    }
}

然后你可以像这样构建字典:

You can then build the dictionary like this:

var dict = leaves.ToDictionary(e => e.Path(), e => e.Value);

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