json 对象的完整路径 [英] Full path of a json object

问题描述

我正在尝试展平一个对象，其中键将是叶节点的完整路径.我可以递归地识别哪些是叶节点，但在尝试构建整个路径时卡住了.

样本输入:

<前>{一:1，二: {三:3},四:{五:5，六: {七:7},八:8},九:9}

输出:

<前>{一:1，'二三':3，'四.五':5，'四.六.七': 7,'四.八':8，九:9}

解决方案

您可以使用递归方法并收集对象的键.这个提议也寻找数组.

function getFlatObject(object) {函数迭代器(o，p){if (o && typeof o === 'object') {Object.keys(o).forEach(function (k) {iter(o[k], p.concat(k));});返回;}路径[p.join('.')] = o;}变量路径 = {};迭代器(对象，[])；返回路径；}var obj = {一:1，二:{三:3}，四:{五:5，六:{七:7}，八:8}，九:9}，路径 = getFlatObject(obj);console.log(path);

I'm trying to flatten an object where the keys will be the full path to the leaf node. I can recursively identify which are the leaf nodes but stuck trying to construct the whole path.

Sample Input:

{
  one: 1,
  two: {
    three: 3
  },
  four: {
    five: 5,
    six: {
      seven: 7
    },
    eight: 8
  },
  nine: 9
}

Output:

{
  one: 1,
  'two.three': 3,
  'four.five': 5,
  'four.six.seven': 7,
  'four.eight': 8,
  nine: 9
}

解决方案

You could use a recursive approch and collect the keys of the object. This proposal looks for arrays as well.

function getFlatObject(object) {
    function iter(o, p) {
        if (o && typeof o === 'object') {
            Object.keys(o).forEach(function (k) {
                iter(o[k], p.concat(k));
            });
            return;
        }
        path[p.join('.')] = o;
    }

    var path = {};
    iter(object, []);
    return path;
}

var obj = { one: 1, two: { three: 3 }, four: { five: 5, six: { seven: 7 }, eight: 8 }, nine: 9 },
    path = getFlatObject(obj);
	
console.log(path);

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