如何 grep 精确的文字字符串(无正则表达式) [英] How to grep exact literal string (no regex)

问题描述

有没有办法grep(或使用另一个命令)来查找确切的字符串，而不使用正则表达式?

例如，如果我想搜索(字面意思):

/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html

我不想经历并逃脱每一个可逃脱的".本质上，我想通过它，就像使用 echo 一样:

$ echo "/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html"/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html

解决方案

使用fgrep，与grep -F相同(匹配固定字符串).

Is there a way to grep (or use another command) to find exact strings, using NO regex?

For example, if I want to search for (literally):

/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html

I don't want to go through and escape every single "escapable". Essentially, I want to pass it through, like I would with echo:

$ echo "/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html"
/some/file"that/has'lotsof"invalid"chars/and.triggers$(#2)[*~.old][3].html

解决方案

Use fgrep, it's the same as grep -F (matches a fixed string).

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