Linux，打印文件中的所有行，而不是以 [英] Linux, Print all lines in a file, NOT starting with

问题描述

我想打印文件的内容，但我想忽略所有以 # 开头的行.我正在尝试使用 grep 和 awk 进行一些操作，但它一直在打印整个文件，或者只是打印以 # 开头的行.我你可以给我一个正确的方法，或者一个 grep/awk 命令，它会打印文件中不以 # 开头的任意行.

I would like to print the contents of a file, but all lines starting with # I want to ignore. I was trying some stuff with grep and awk, but it kept printing the whole file, or just printed the lines starting with #. I you could give me a push in the right way, or a grep/awk command that would print anyline in the file that does not start with #.

推荐答案

使用grep的-v选项来否定条件:

Use the -v option of grep to negate the condition:

grep -v '^#' file

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