Linux中，打印所有行的文件，而不是与开始 [英] Linux, Print all lines in a file, NOT starting with

问题描述

我想打印一个文件的内容，但以＃开头的所有行我想忽略。我尝试一些东西使用grep和awk，但它一直在打印整个文件，或只是打印开始＃行。我你能给我以正确的方式一推，或的grep / awk命令，将不以＃开头的文件中打印苯胺。

I would like to print the contents of a file, but all lines starting with # I want to ignore. I was trying some stuff with grep and awk, but it kept printing the whole file, or just printed the lines starting with #. I you could give me a push in the right way, or a grep/awk command that would print anyline in the file that does not start with #.

推荐答案

使用的grep 的 -v 选项否定条件：

grep -v '^#' file

这篇关于Linux中，打印所有行的文件，而不是与开始的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！