如何使用 Jackson 反序列化以秒为单位的时间戳? [英] How do I deserialize timestamps that are in seconds with Jackson?

查看:134
本文介绍了如何使用 Jackson 反序列化以秒为单位的时间戳?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一些 JSON 以秒为单位的时间戳(即 Unix 时间戳):

I've got some JSON that has timestamps in seconds (i.e. a Unix timestamp):

{"foo":"bar","timestamp":1386280997}

要求 Jackson 将其反序列化为带有时间戳的 DateTime 字段的对象导致 1970-01-17T01:11:25.983Z,这是纪元之后不久的时间,因为 Jackson 假设它是以毫秒为单位.除了撕开 JSON 并添加一些零之外,我如何让 Jackson 理解 seconds 时间戳?

Asking Jackson to deserialize this into an object with a DateTime field for the timestamp results in 1970-01-17T01:11:25.983Z, a time shortly after the epoch because Jackson is assuming it to be in milliseconds. Aside from ripping apart the JSON and adding some zeros, how might I get Jackson to understand the seconds timestamp?

推荐答案

我写了一个自定义的deserializer 以秒为单位处理时间戳(Groovy 语法).

I wrote a custom deserializer to handle timestamps in seconds (Groovy syntax).

class UnixTimestampDeserializer extends JsonDeserializer<DateTime> {
    Logger logger = LoggerFactory.getLogger(UnixTimestampDeserializer.class)

    @Override
    DateTime deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
        String timestamp = jp.getText().trim()

        try {
            return new DateTime(Long.valueOf(timestamp + '000'))
        } catch (NumberFormatException e) {
            logger.warn('Unable to deserialize timestamp: ' + timestamp, e)
            return null
        }
    }
}

然后我注释了我的 POGO 以将其用作时间戳:

And then I annotated my POGO to use that for the timestamp:

class TimestampThing {
    @JsonDeserialize(using = UnixTimestampDeserializer.class)
    DateTime timestamp

    @JsonCreator
    public TimestampThing(@JsonProperty('timestamp') DateTime timestamp) {
        this.timestamp = timestamp
    }
}

这篇关于如何使用 Jackson 反序列化以秒为单位的时间戳?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆