Mongodb 同时聚合(计数)多个字段 [英] Mongodb aggregate (count) on multiple fields simultaneously
问题描述
我有这样的文档:
{
"_id" : "someuniqueeventid",
"event" : "event_type_1",
"date" : ISODate("2014-01-14T00:00:00Z"),
}
我想按event
"分组并计算一周中每一天发生的每种事件类型的数量.基本上,我想得到类似的东西:
I want to group by "event
" and count how many of each event type occured in each day of the week. Basically, I want to get something like:
{
"_id": "event_type_1",
"1": "number of event_type_1 for Monday",
"2": "number of event_type_1 for Tuesday",
...
},
{
"_id": "event_type_2",
...
}
不幸的是,我被困在:
db.data.aggregate([ {$project: {date_of_week: {$dayOfWeek: "$date"}, event: "$event"}},
{$group: {_id: "$event", .... } ])
有什么想法吗?
推荐答案
聚合框架不会基于数据创建键,你也不应该这样做,因为数据"不是关键但实际上是数据,所以你应该坚持这个模式.
The aggregation framework won't create keys based on data, nor should you even be doing so as "data" is not a key but actually data, so you should stick to the pattern.
这意味着你基本上可以这样做:
That means you can basically just do this:
db.data.aggregate([
{ "$group": {
"_id": {
"event_type": "$event",
"day": { "$dayOfWeek": "$date" }
},
"count": { "$sum": 1 }
}}
])
这将计算每个事件每周发生的次数,尽管在输出中的多个文档中,但这很容易更改为每个事件的单个文档:
And that will count the occurrences per day of week per event, albeit in multiple documents in the output, but this is easy to change to a single document per event:
db.data.aggregate([
{ "$group": {
"_id": {
"event_type": "$event",
"day": { "$dayOfWeek": "$date" }
},
"count": { "$sum": 1 }
}},
{ "$group": {
"_id": "$_id.event_type",
"days": { "$push": { "day": "$_id.day", "count": "$count" } }
}}
])
这是一个数组形式,但它仍然保存着你想要的结果.
And that is in an array form, but it still holds the results you want.
如果你真的一心想要做你的确切形式,那么你想做这样的事情:
If you are really bent on doing your exact form then you want to do something like this:
db.data.aggregate([
{ "$group": {
"_id": "$event",
"1": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 1 ] },
1,
0
]
}
},
"2": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 2 ] },
1,
0
]
}
},
"3": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 3 ] },
1,
0
]
}
},
"4": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 4 ] },
1,
0
]
}
},
"5": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 5 ] },
1,
0
]
}
},
"6": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 6 ] },
1,
0
]
}
},
"7": {
"$sum": {
"$cond": [
{ "$eq": [{ "$dayOfWeek": "$date" }, 7 ] },
1,
0
]
}
}
}}
)
但这真的很长,所以恕我直言,我会坚持第一个或第二个解决方案,因为它们更短且更易于阅读.
But that is really long winded so IMHO I would stick with the first or maybe second solution as they are shorter and more easy to read.
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