远程服务器返回错误：（405）不允许的方法。 WCF REST服务 [英] The remote server returned an error: (405) Method Not Allowed. WCF REST Service
问题描述
这个问题已经在其他地方问，但那些东西不是我的问题的解决方案。
This question is already asked elsewhere but those things are not the solutions for my issue.
这是我的服务
[WebInvoke(UriTemplate = "", Method = "POST")]
public SampleItem Create(SampleItem instance)
{
// TODO: Add the new instance of SampleItem to the collection
// throw new NotImplementedException();
return new SampleItem();
}
我有这个code拨打上述服务
I have this code to call the above service
XElement data = new XElement("SampleItem",
new XElement("Id", "2"),
new XElement("StringValue", "sdddsdssd")
);
System.IO.MemoryStream dataSream1 = new MemoryStream();
data.Save(dataSream1);
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://localhost:2517/Service1/Create");
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
// You need to know length and it has to be set before you access request stream
request.ContentLength = dataSream1.Length;
using (Stream requestStream = request.GetRequestStream())
{
dataSream1.CopyTo(requestStream);
byte[] bytes = dataSream1.ToArray();
requestStream.Write(bytes, 0, Convert.ToInt16(dataSream1.Length));
requestStream.Close();
}
WebResponse response = request.GetResponse();
我得到一个例外，在最后一行：
I get an exception at the last line:
远程服务器返回错误：（405）不允许的方法。不知道为什么会这样，我试图改变主机从VS服务器IIS还但结果没有变化。让我知道如果u需要更多的信息
The remote server returned an error: (405) Method Not Allowed. Not sure why this is happening i tried changing the host from VS Server to IIS also but no change in result. Let me know if u need more information
推荐答案
第一件事情就是要知道你的REST服务的准确网址。既然你已经指定的http：//本地主机：2517 /服务1 /创建现在只是尝试从IE浏览器相同的URL，你应该得到的方法不得作为你的创建方法定义为WebInvoke和IE做了WebGet。
First thing is to know the exact URL for your REST Service. Since you have specified http://localhost:2517/Service1/Create now just try to open the same URL from IE and you should get method not allowed as your Create Method is defined for WebInvoke and IE does a WebGet.
现在请确保您有SampleItem在同一个命名空间中定义的服务器上的客户端应用程序或确保XML字符串您正在构建有服务，以确定适当的名称空间的样本对象的XML字符串可以反序列化回服务器的对象。
Now make sure that you have the SampleItem in your client app defined in the same namespace on your server or make sure that the xml string you are building has the appropriate namespace for the service to identify that the xml string of sample object can be deserialized back to the object on server.
我有SampleItem我的服务器上定义的，如下所示：
I have the SampleItem defined on my server as shown below:
namespace SampleApp
{
public class SampleItem
{
public int Id { get; set; }
public string StringValue { get; set; }
}
}
相当于我SampleItem XML字符串是如下：
The xml string corresponding to my SampleItem is as below:
<SampleItem xmlns="http://schemas.datacontract.org/2004/07/SampleApp" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><Id>6</Id><StringValue>from client testing</StringValue></SampleItem>
现在我用下面的方法来执行POST到REST服务：
Now i use the below method to perform a POST to the REST service :
private string UseHttpWebApproach<T>(string serviceUrl, string resourceUrl, string method, T requestBody)
{
string responseMessage = null;
var request = WebRequest.Create(string.Concat(serviceUrl, resourceUrl)) as HttpWebRequest;
if (request != null)
{
request.ContentType = "application/xml";
request.Method = method;
}
//var objContent = HttpContentExtensions.CreateDataContract(requestBody);
if(method == "POST" && requestBody != null)
{
byte[] requestBodyBytes = ToByteArrayUsingDataContractSer(requestBody);
request.ContentLength = requestBodyBytes.Length;
using (Stream postStream = request.GetRequestStream())
postStream.Write(requestBodyBytes, 0, requestBodyBytes.Length);
}
if (request != null)
{
var response = request.GetResponse() as HttpWebResponse;
if(response.StatusCode == HttpStatusCode.OK)
{
Stream responseStream = response.GetResponseStream();
if (responseStream != null)
{
var reader = new StreamReader(responseStream);
responseMessage = reader.ReadToEnd();
}
}
else
{
responseMessage = response.StatusDescription;
}
}
return responseMessage;
}
private static byte[] ToByteArrayUsingDataContractSer<T>(T requestBody)
{
byte[] bytes = null;
var serializer1 = new DataContractSerializer(typeof(T));
var ms1 = new MemoryStream();
serializer1.WriteObject(ms1, requestBody);
ms1.Position = 0;
var reader = new StreamReader(ms1);
bytes = ms1.ToArray();
return bytes;
}
现在我调用上面的方法，如：
Now i call the above method as shown:
SampleItem objSample = new SampleItem();
objSample.Id = 7;
objSample.StringValue = "from client testing";
string serviceBaseUrl = "http://localhost:2517/Service1";
string resourceUrl = "/Create";
string method="POST";
UseHttpWebApproach<SampleItem>(serviceBaseUrl, resourceUrl, method, objSample);
我在客户端定义好SampleItem对象。如果你想建立客户机上的XML字符串并传递，那么你可以用下面的方法：
I have the SampleItem object defined in the client side as well. If you want to build the xml string on the client and pass then you can use the below method:
private string UseHttpWebApproach(string serviceUrl, string resourceUrl, string method, string xmlRequestBody)
{
string responseMessage = null;
var request = WebRequest.Create(string.Concat(serviceUrl, resourceUrl)) as HttpWebRequest;
if (request != null)
{
request.ContentType = "application/xml";
request.Method = method;
}
//var objContent = HttpContentExtensions.CreateDataContract(requestBody);
if(method == "POST" && requestBody != null)
{
byte[] requestBodyBytes = ASCIIEncoding.UTF8.GetBytes(xmlRequestBody.ToString());
request.ContentLength = requestBodyBytes.Length;
using (Stream postStream = request.GetRequestStream())
postStream.Write(requestBodyBytes, 0, requestBodyBytes.Length);
}
if (request != null)
{
var response = request.GetResponse() as HttpWebResponse;
if(response.StatusCode == HttpStatusCode.OK)
{
Stream responseStream = response.GetResponseStream();
if (responseStream != null)
{
var reader = new StreamReader(responseStream);
responseMessage = reader.ReadToEnd();
}
}
else
{
responseMessage = response.StatusDescription;
}
}
return responseMessage;
}
和调用上述方法将如下所示：
And the call to the above method would be as shown below:
string sample = "<SampleItem xmlns=\"http://schemas.datacontract.org/2004/07/XmlRestService\" xmlns:i=\"http://www.w3.org/2001/XMLSchema-instance\"><Id>6</Id><StringValue>from client testing</StringValue></SampleItem>";
string serviceBaseUrl = "http://localhost:2517/Service1";
string resourceUrl = "/Create";
string method="POST";
UseHttpWebApproach<string>(serviceBaseUrl, resourceUrl, method, sample);
请注意：只要确保你的网址是否正确
NOTE: Just make sure that your URL is correct
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