正则表达式替换所有字符,除了数字 [英] RegEx for replacing all characters apart from numbers
问题描述
如果我有一个字符串的数据在它的数字。这种模式是不相符的。我想从字符串且只有被定义为允许一个字符提取所有数字。我想正则表达式可能是这样做的最简单的方法。你能提供一个正则表达式图案可能做到这一点,因为我觉得正则表达式是巫术,只有正则表达式医药男人知道它是如何工作
例如:/
Q1W2EE3R45T=12345
WWED456J=456
ABC123=123
N123=N123// N是允许的字符
更新:这是我的code:
VAR数据= Value.Split(新的char [] {','},StringSplitOptions.RemoveEmptyEntries);
数据= data.Select(X => Regex.Replace(X,??????,的String.Empty))的ToArray()。
字符串numbersOnly = Regex.Replace(STR,@[^ \ D]的String.Empty);
使用 Regex.Replace(字符串,字符串,字符串)
的静态方法。
要允许 N
,你可以换着花样给 [^ \ DN]
。如果你正在寻找 N
,以及你可以使用的 RegexOptions.IgnoreCase
或类改为 [^ \ DNN]
If I have a string of data with numbers in it. This pattern is not consistent. I would like to extract all numbers from the string and only a character that is defined as allowed. I thought RegEx might be the easiest way of doing this. Could you provide a regex patter that may do this as I think regex is voodoo and only regex medicine men know how it works
eg/
"Q1W2EE3R45T" = "12345"
"WWED456J" = "456"
"ABC123" = "123"
"N123" = "N123" //N is an allowed character
UPDATE: Here is my code:
var data = Value.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries);
data = data.Select(x => Regex.Replace(x, "??????", String.Empty)).ToArray();
String numbersOnly = Regex.Replace(str, @"[^\d]", String.Empty);
Using Regex.Replace(string,string,string)
static method.
To allow N
you can change the pattern to [^\dN]
. If you're looking for n
as well you can either apply RegexOptions.IgnoreCase
or change the class to [^\dnN]
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