在 SKScene 中转至 UIViewController [英] Segue in SKScene to UIViewController

问题描述

在我的 GameScene.swift 文件中，我试图像这样执行回到我的菜单视图控制器的 segue:

In my GameScene.swift file, I am trying to perform a segue back to my Menu View Controller like so:

func returnToMainMenu(){
    var vc: UIViewController = UIViewController()
    vc = self.view!.window!.rootViewController!
    vc.performSegueWithIdentifier("menu", sender: vc)
}

该方法在节点被点击时运行:

This method is run when a node is tapped:

override func touchesEnded(touches: NSSet, withEvent event: UIEvent) {
    for touch: AnyObject in touches {
        let location = touch.locationInNode(self)
        if gameOn == false{
            if restartBack.containsPoint(location){
                self.restartGame()
            }
            else if menuBack.containsPoint(location){
                self.returnToMainMenu()
            }
            else if justBegin == true{
                self.restartGame()
            }
        }
    }
}

menuBack 是返回菜单的按钮.每次我运行这段代码时，都会抛出一个 NSException:

Where menuBack is the button back to the menu. Every time I run this code, I am thrown an NSException:

Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<ProxyBlock.Menu: 0x165a3e90>) has no segue with identifier 'menu''

我检查了我的 segue 标识符，它确实是菜单".

I checked my segue's identifier and it was indeed "menu".

推荐答案

你正在调用根 viewController 上的 segue.我认为这就是问题所在.您需要在场景的 viewController 上调用 segue(我假设您已经创建了 segue，因此在根 viewController 上找不到它).

You are calling the segue on the root viewController. I think that is the problem. You need to call the segue on the scene's viewController instead (where I am assuming you have created the segue, hence it is not being found on the root viewController).

现在的问题是 SKScene 不能直接访问它的 viewController，而只能访问它所在的视图.您需要手动创建指向它的指针.这可以通过为 SKScene 创建一个属性来完成:

Now the problem is that an SKScene does not have direct access to it's viewController, but just the view in which it is contained. You need to create a pointer to it manually. This can be done by creating a property for the SKScene:

class GameScene: SKScene {
    weak var viewController: UIViewController?
    ...
}

然后，在 viewController 类中，就在 skView.presentScene(scene)

Then, in the viewController class, just before skView.presentScene(scene)

scene.viewController = self

现在，您可以直接访问 viewController.只需在这个 viewController 上调用 segue:

Now, you can access the viewController directly. Simply call the segue on this viewController:

func returnToMainMenu(){
    viewController?.performSegueWithIdentifier("menu", sender: vc)
}

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