使用 Newtonsoft C# 从 json 转换为 Enum [英] Convert from json to Enum with Newtonsoft C#

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问题描述

如何将 json 反序列化为 C# 中的枚举列表?

How could i deserialize json into a List of enum in C#?

我写了以下代码:

  //json "types" : [ "hotel", "spa" ]

   public enum eType 
    {
      [Description("hotel")] 
      kHotel, 
      [Description("spa")]
      kSpa
    }

    public class HType 
    { 
       List<eType> m_types; 

        [JsonProperty("types")]
         public List<eType> HTypes { 
         get
          {
               return m_types;
          } 
           set
          {
             // i did this to try and decide in the setter
             // what enum value should be for each type
             // making use of the Description attribute
             // but throws an exception 
          }

}}

       //other class 

               var hTypes = JsonConvert.DeserializeObject<HType>(json);

推荐答案

自定义转换器可能会有所帮助.

A custom converter may help.

var hType = JsonConvert.DeserializeObject<HType>(
                            @"{""types"" : [ ""hotel"", ""spa"" ]}",
                            new MyEnumConverter());

<小时>

public class HType
{
    public List<eType> types { set; get; }
}

public enum eType
{
    [Description("hotel")]
    kHotel,
    [Description("spa")]
    kSpa
}

public class MyEnumConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(eType);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var eTypeVal =  typeof(eType).GetMembers()
                        .Where(x => x.GetCustomAttributes(typeof(DescriptionAttribute)).Any())
                        .FirstOrDefault(x => ((DescriptionAttribute)x.GetCustomAttribute(typeof(DescriptionAttribute))).Description == (string)reader.Value);

        if (eTypeVal == null) return Enum.Parse(typeof(eType), (string)reader.Value);

        return Enum.Parse(typeof(eType), eTypeVal.Name);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

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