使用newtonsoft C＃删除json的子节点 [英] C# remove json child node using newtonsoft

问题描述

我正在开发使用.NET 3.5的WPF C＃应用程序。
我用newtonsoft库解析JSON字符串。

I am developing an app using c# wpf in .net 3.5. I use newtonsoft library to parse the json string.

我想知道如何删除JSON的子节点。

I want to know how to remove a child node of json.

例如，
我的JSON数据=

For example, My json data =

{"employees":[
{"firstName":"John", "lastName":"Doe"}, 
{"firstName":"Anna", "lastName":"Smith"}, 
{"firstName":"Peter", "lastName":"Jones"}]}

功能

jobject.Remove("employees");

成功地删除所有的节点

我想知道如何只除去第一个雇员的细节。

I would like to know how to remove the first employee detail alone.

推荐答案

一旦你解析你的JSON成 JObject ，员工财产将是一个 JArray 。在 JArray 类有你要找的方法，如 JArray.RemoveAt

Once you parse your json into a JObject, the employees property will be a JArray. The JArray class has methods you're looking for, such as JArray.RemoveAt

下面的代码将做你想做的。

The following code will do what you want

string json =
@"{
    ""employees"":[
        { ""firstName"":""John"", ""lastName"":""Doe""}, 
        { ""firstName"":""Anna"", ""lastName"":""Smith""}, 
        { ""firstName"":""Peter"", ""lastName"":""Jones""}
    ]
}";

dynamic obj = JObject.Parse(json);
(obj.employees as JArray).RemoveAt(0);

// obj now only has "Anna Smith" and "Peter Jones"

动态介绍在.NET 4.0中，因此对于3.5，你会使用这样的事情，而不是

dynamic was introduced in .NET 4.0, so for 3.5 you'd use something like this instead

JObject obj = JObject.Parse(json);
(obj["employees"] as JArray).RemoveAt(0);

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