在 gulp 任务中很好地抛出错误 [英] Nicely throwing an error in gulp task

问题描述

我正在创建一个在某些情况下可能会失败的 gulp 任务.

gulp.task('favicon', function () {尝试 {require('child_process').execSync('icotool --version');} 捕捉( e ) {var err = new Error('生成 favicon 需要 Unix bash 和 icotool');抛出错误；}返回 gulp.src('', {read: false}).管道(外壳(['./generate-favicon.sh']));});

当通过 gulp 运行我的任务并遇到错误时，该错误将呈现得相当难看.我想以一种方式呈现错误，例如，jslint gulp-util 的 PluginError.

它实际上只是在其中创建一个 PluginError 并抛出它，但这似乎不太正确.另一个不太好的解决方案是设置

err.showStack = false;

至少有更好的错误输出.gulp.task.Error 会很好.

解决方案

据我所知，从 gulp 中抛出错误并不是很好.但是我发现了这个我曾经为我工作的博客条目.

http://gotofritz.net/博客/geekery/how-to-generate-error-in-gulp-task/

编辑:gulp-util已弃用.相反，请使用 plugin-error 包.p>

我的例子:

var gulp = require('gulp');var error = require('plugin-error');gulp.task('部署'，函数(cb){if(typeof(specialId) === '未定义') {var err = new PluginError({插件:'部署'，消息:'specialId 为空.'});}}

I am creating a gulp task which might fail under certain circumstances.

gulp.task('favicon', function () {
  try {
    require('child_process').execSync('icotool --version');
  } catch( e ) {
    var err = new Error( 'Unix bash and icotool required for generating favicon' );
    throw err;
  }

  return gulp.src('', {read: false})
    .pipe(shell([
      './generate-favicon.sh'
    ]));
});

When running my task via gulp and running into the error, the error will be presented rather ugly. I would like to present the error in a way as it is done by e.g. jslint gulp-util's PluginError.

It actually works to just create a PluginError there and throw it but that doesn't seem quite right. Another solution not that nice would be to set

err.showStack = false;

for at least a little nicer error output. A gulp.task.Error would be nice.

解决方案

From what I've seen its not great to throw an error from gulp. But I found this blog entry that I used to work for me.

http://gotofritz.net/blog/geekery/how-to-generate-error-in-gulp-task/

Edit: gulp-util has been deprecated. Instead, use the plugin-error package.

My Example:

var gulp = require('gulp');
var error = require('plugin-error');
gulp.task('deploy', function(cb) {
  if(typeof(specialId) === 'undefined') {
    var err = new PluginError({
      plugin: 'deploy',
      message: 'specialId is empty.'
    });
  }
}

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