LibGDX 画线 [英] LibGDX draw line

问题描述

我正在尝试使用 libGDX 制作类似弹弓的东西.

I'm trying to make something like a slingshot using libGDX.

我的代码

if (Gdx.input.isTouched()) {

        ShapeRenderer sr = new ShapeRenderer();
        sr.setColor(Color.BLACK);
        sr.setProjectionMatrix(camera.combined);

        sr.begin(ShapeType.Line);
        sr.line(player.getLeft().x, player.getLeft().y,
                Global.game_touch_position.x, Global.game_touch_position.y);
        sr.line(player.getRight().x, player.getRight().y,
                Global.game_touch_position.x, Global.game_touch_position.y);
        sr.end();

    }

这样做我会得到输出这看起来很糟糕，如果我在我的 android 手机上调试，logcat 会被消息发送垃圾邮件

Doing this i will have the output This looks awful, and if I debug on my android phone , the logcat is spammed by the message

02-17 18:55:27.371: D/dalvikvm(7440): GC_CONCURRENT freed 1884K, 40% free 8287K/13635K, paused 15ms+2ms, total 40ms

而且滞后，当我触摸屏幕时，我有 30 fps，当我不触摸时，我有 60...

And lags, I have like 30 fps when i touch the screen , and 60 when i don't...

我还需要画粗一点的线，所以当线变大时，我必须把它加粗，看起来很酷.

I also need to draw the line with a little bit of thickness, so when the line is bigger, i will have to make it thicker, to give a cool look.

在 libgdx 中绘制简单线条的最佳方法是什么?如果我找不到任何答案，我可能会从线的一点到另一点画圈......这看起来不错，但看起来不像弹弓......

Which is the best way to draw a simple line in libgdx ? If I won't find any answer probably i'm going to draw circles from a point of the line to the other..this would look ok , but won't look like a slingshot...

有什么帮助吗?

推荐答案

我只是在 helper 或 utils 类中有这样的东西.我通常用它来调试和可视化正在发生的事情.

I just have something like this in a helper or utils class. I usually use it for debugging and visualizing whats going on.

private static ShapeRenderer debugRenderer = new ShapeRenderer();

    public static void DrawDebugLine(Vector2 start, Vector2 end, int lineWidth, Color color, Matrix4 projectionMatrix)
    {
        Gdx.gl.glLineWidth(lineWidth);
        debugRenderer.setProjectionMatrix(projectionMatrix);
        debugRenderer.begin(ShapeRenderer.ShapeType.Line);
        debugRenderer.setColor(color);
        debugRenderer.line(start, end);
        debugRenderer.end();
        Gdx.gl.glLineWidth(1);
    }

    public static void DrawDebugLine(Vector2 start, Vector2 end, Matrix4 projectionMatrix)
    {
        Gdx.gl.glLineWidth(2);
        debugRenderer.setProjectionMatrix(projectionMatrix);
        debugRenderer.begin(ShapeRenderer.ShapeType.Line);
        debugRenderer.setColor(Color.WHITE);
        debugRenderer.line(start, end);
        debugRenderer.end();
        Gdx.gl.glLineWidth(1);
    }

现在我可以轻松地从任何我喜欢的投影矩阵上画一条线.

Now I can easily draw a line from anywhere I like on any projection matrix I want.

HelperClass.DrawDebugLine(new Vector2(0,0), new Vector2(100,100), camera.combined);

你想在其他 SpriteBatch 开始和结束之外绘制.如果您想在每帧中创建很多行，最好在单独的静态方法中开始和结束 ShapeRenderer，或者将其公开并根据您的需要自行完成.

You want to draw outside the other SpriteBatch begin and end. And if you want to make a lot of lines each frame you are better off beginning and ending the ShapeRenderer in a separate static method or make it public and do it yourself depending on your needs.

显然，您可以为更多形状或更多重载创建更多方法.

Obviously you can create more methods for more shapes or more overloads.

这篇关于LibGDX 画线的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！