getline() 即使在 clear() 之后也会先跳过 [英] getline() skipping first even after clear()

问题描述

所以我有一个函数可以不断跳过第一个 getline 并直接跳到第二个 getline.我试图清除缓冲区但仍然没有运气，这是怎么回事?

So I have a function that keeps skipping over the first getline and straight to the second one. I tried to clear the buffer but still no luck, what's going on?

void getData(char* strA, char* strB)
{
    cout << "Enter String 1: ";               // Shows this line
    cin.clear();
    cin.getline(strA, 50);                    // 50 is the character limit, Skipping Input

    cout << endl << "Enter String 2: ";       // Showing This Line
    cin.clear();
    cin.getline(strB, 50);                   // Jumps Straight to this line
}

推荐答案

确保你没有使用 cin >>字符串.在调用函数之前.如果你使用 cin >>str 然后要使用getline(cin, str)，必须先调用cin.ignore().

Make sure you didn't use cin >> str. before calling the function. If you use cin >> str and then want to use getline(cin, str), you must call cin.ignore() before.

string str;
cin >> str;
cin.ignore(); // ignores 
 that cin >> str has lefted (if user pressed enter key)
getline(cin, str);

如果使用 c 字符串:

In case of using c-strings:

char buff[50];
cin.get(buff, 50, ' ');
cin.ignore();
cin.getline(buff, 50);

添加:你的错误可能不在函数本身，而是在调用函数之前.cin 流必须在第一个 cin.getline 中仅读取换行符 '.

ADD: Your wrong is not probably in the function itself, but rather before calling the function. The stream cin have to read only a new line character ' in first cin.getline.

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