使用 strcmp 比较 char 数组中的字符 [英] compare a character on a char array by using strcmp

问题描述

我想使用 strcmp 在 char 数组中查找特定字符.例如，我想检测 . 在文本上的索引号.

I would like to use strcmp to find a specific character on a char array. For example, I would like to detect the index number where . is on the text.

char host[100] = "hello.world";
size_t i=0;
for(i=0;i<strlen(host);i++){
   if(strcmp(host[strlen(host)-i], ".")){
        printf("%d
",i);
   }
}

然而，它输出 传递 'strcmp' 的参数 1 使指针来自整数而不进行强制转换".我注意到 char 数组是一个 int，但我无法弄清楚我应该如何传递 char 索引.你能告诉我应该如何使用这个功能吗?

however, it outputs "passing argument 1 of 'strcmp' makes pointer from integer without a cast ". I notice that char array is a int, but I could not figure out how I should have passed the char index. Could you please tell me how I should have used the function?

推荐答案

这一行:

if(strcmp(host[strlen(host)-i], ".")){

应该看起来像这样(添加和号，以将指针传递给 char 数组的元素):

should look like this (ampersand added, to pass pointer to the char array's element):

if(strcmp(&host[strlen(host)-i], ".")){

确实，正如其他人已经指出的那样，strcmp 并不是完成这项任务的最佳工具.您可以使用 strchr 或仅将字符与 '==' 运算符进行比较，如果您喜欢滚动自己的循环.

It's true, though, as others already pointed out, that strcmp is not the best tool for the task. You can use strchr or just compare the characters with '==' operator, if you prefer to roll your own loop.

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