通过使用STRCMP比较char阵列上的字符 [英] compare a character on a char array by using strcmp

问题描述

我想用的strcmp找一个char阵列上的特定字符。例如，我想检测的索引号，其中。是文本。

I would like to use strcmp to find a specific character on a char array. For example, I would like to detect the index number where . is on the text.

char host[100] = "hello.world";
size_t i=0;
for(i=0;i<strlen(host);i++){
   if(strcmp(host[strlen(host)-i], ".")){
        printf("%d\n",i);
   }
}

然而，它输出过客的strcmp'的参数1时将整数指针，未作类型转换。我注意到，字符数组是一个int值，不过我无法弄清楚如何我应该已经通过了字符的索引。你能告诉我，我应该怎么使用了功能？

however, it outputs "passing argument 1 of 'strcmp' makes pointer from integer without a cast ". I notice that char array is a int, but I could not figure out how I should have passed the char index. Could you please tell me how I should have used the function?

推荐答案

这行：

if(strcmp(host[strlen(host)-i], ".")){

应该像这样（加符号，传递指针字符数组的元素）：

should look like this (ampersand added, to pass pointer to the char array's element):

if(strcmp(&host[strlen(host)-i], ".")){

这是真的，但是，正如其他人已经指出的， STRCMP 不是任务的最佳工具。您可以使用和strchr 或只是字符'=='操作，如果你preFER推出自己的循环比较。

It's true, though, as others already pointed out, that strcmp is not the best tool for the task. You can use strchr or just compare the characters with '==' operator, if you prefer to roll your own loop.

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