如何在MVC 3使用正则表达式剃刀 [英] how to use regex in MVC 3 with razor

问题描述

当我使用MVC 3剃刀它的做工精细，但是当我使用@section头{写一个正则表达式
}，他们无法正常工作

 函数isValidEmailAddress（EMAILADDRESS）{
            VAR模式=新RegExp(/^((\"[\\w-\\s]+\")|([\\w-]+(?:\\.[\\w-]+)*)|(\"[\\w-\\s]+\")([\\w-]+(?:\\.[\\w-]+)*))(@((?:[\\w-]+\\.)*\\w[\\w-]{0,66})\\.([a-z]{2,6}(?:\\.[a-z]{2})?)$)|(@\\[?((25[0-5]\\.|2[0-4][0-9]\\.|1[0-9]{2}\\.|[0-9]{1,2}\\.))((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\\.){2}(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\\]?$)/i);
            返回pattern.test（EMAILADDRESS）;
        }
 

它有@这样的给我的错误

  

分析器错误说明：的解析过程中出现错误
  所需的资源来服务这个请求。请查看以下
  具体分析错误详细信息并修改源文件
  适当。分析器错误信息：\\是不是开始有效
  一个code座。只有标识符，关键字，注释，（和{是
  有效的。

解决方案

一个更简洁的选择是通过将另@在它面前逃脱@（@@）

 函数isValidEmailAddress（EMAILADDRESS）{
    VAR模式=新RegExp(/^((\"[\\w-\\s]+\")|([\\w-]+(?:\\.[\\w-]+)*)|(\"[\\w-\\s]+\")([\\w-]+(?:\\.[\\w-]+)*))(@@((?:[\\w-]+\\.)*\\w[\\w-]{0,66})\\.([a-z]{2,6}(?:\\.[a-z]{2})?)$)|(@@\\[?((25[0-5]\\.|2[0-4][0-9]\\.|1[0-9]{2}\\.|[0-9]{1,2}\\.))((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\\.){2}(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\\]?$)/i);
    返回pattern.test（EMAILADDRESS）;
}
 

when i use MVC 3 with razor it's work fine but when i write a regex using @section head{ } that they not work

 function isValidEmailAddress(emailAddress) {
            var pattern = new RegExp(/^(("[\w-\s]+")|([\w-]+(?:\.[\w-]+)*)|("[\w-\s]+")([\w-]+(?:\.[\w-]+)*))(@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{2})?)$)|(@\[?((25[0-5]\.|2[0-4][0-9]\.|1[0-9]{2}\.|[0-9]{1,2}\.))((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\.){2}(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\]?$)/i);
            return pattern.test(emailAddress);
        }

it have @ so that's give me error that

Parser Error Description: An error occurred during the parsing of a resource required to service this request. Please review the following specific parse error details and modify your source file appropriately. Parser Error Message: "\" is not valid at the start of a code block. Only identifiers, keywords, comments, "(" and "{" are valid.

解决方案

A neater option is to escape the @ by placing another @ in front of it (@@)

function isValidEmailAddress(emailAddress) {
    var pattern = new RegExp(/^(("[\w-\s]+")|([\w-]+(?:\.[\w-]+)*)|("[\w-\s]+")([\w-]+(?:\.[\w-]+)*))(@@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{2})?)$)|(@@\[?((25[0-5]\.|2[0-4][0-9]\.|1[0-9]{2}\.|[0-9]{1,2}\.))((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\.){2}(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[0-9]{1,2})\]?$)/i);
    return pattern.test(emailAddress);
}

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