单击按钮打开模式 [英] opening a modal with the click of a button

问题描述

接下来的代码使用了一个 Modal react 组件:

导出类 AddWorkLogEditor 扩展 React.Component {构造函数(道具){超级(道具)；this.addWorkLog = this.addWorkLog.bind(this);this.onOpenModal = this.onOpenModal.bind(this);this.onCloseModal = this.onCloseModal.bind(this);这个.state = {打开:真};}onOpenModal() {this.setState({open: this.props.openModal});}onCloseModal() {this.setState({open:false});}addWorkLog() {}使成为() {常量 bstyle = {背景颜色:'绿色'，文本对齐:左"，paddingLeft: '0px',白颜色'};常量 {open} = this.state;返回 (
<Modal open={open} onClose={this.onCloseModal} little><h3>hi gi</h3><按钮 bsStyle="success" bsSize="small" onClick ={(ev) =>{console.log(ev)} }>保存</按钮></模态></div>);}}

我正在尝试使用:

addWorkLog(){返回 <AddWorkLogEditor/>;}

和

 createAddWorkLogButton () {返回 (<button style={ { color: '#007a86'} } onClick={this.addWorkLog} >添加工作日志</button>);}

我的意思是，单击此按钮后，什么都没有显示.还有另一种方式来调用该模态吗?我正在从以下位置导入模态:

从react-responsive-modal"导入模态

解决方案

您试图仅在单击按钮后才呈现模式，虽然这对于非反应环境来说是很自然的，但在反应中它以不同的方式工作.在最简单的解决方案中，应该始终呈现 Modal，并且当用户单击按钮时，您将 modal open 属性更改为 true.

{/* 你页面的所有标记 */}<按钮点击={() =>this.setState({showModal: true})}>添加工作日志</button>{/* 还要别的吗 */}{/* modal 在这里，但它被隐藏了 */}<Modal open={this.state.showModal}>...</Modal>

或者，您可以完全跳过模态渲染，直到 showModal 变为 true.

this.state.showModal &&<Modal open>...</Modal>

The next code uses a Modal react component:

export class AddWorkLogEditor extends React.Component {
    constructor(props) {
        super(props);

        this.addWorkLog = this.addWorkLog.bind(this);       
        this.onOpenModal = this.onOpenModal.bind(this);
        this.onCloseModal = this.onCloseModal.bind(this);
        this.state = {
             open:true

           };
      }

  onOpenModal() {
     this.setState({open: this.props.openModal});
  }

  onCloseModal() {
     this.setState({open:false});
  }

  addWorkLog() {

   }



 render() {
      const bstyle = {
         backgroundColor: 'green',
         textAlign:"left",
         paddingLeft: '0px',
         color: 'white'
    };
 const {open} = this.state;
       return (
           <div>
                <Modal open={open} onClose={this.onCloseModal} little>
                <h3>hi gi</h3>

                 <Button bsStyle="success" bsSize="small" onClick ={(ev) => {console.log(ev)} }> Save </Button>
                 </Modal>
            </div>
       );
    }
}

I am trying to call it using:

addWorkLog()
{
      return <AddWorkLogEditor/>;
}

and

 createAddWorkLogButton () {

    return (
        <button style={ { color: '#007a86'} } onClick={this.addWorkLog} >Add Work Log</button>
    );
 }

I mean, after I click at this button nothing shows up. Is there another way to call that modal? I am importing the modal from:

import Modal from 'react-responsive-modal'

解决方案

You are trying to render the modal only once the button is clicked, while that's quite natural for non-react environments, in react it works in a different way. In the simplest solution the Modal should be always rendered, and when a user clicks the button you change the modal open property to true.

{ /* all the markup of your page */ }
<button onClick={() => this.setState({showModal: true})}>Add Work Log</button>
{ /* anything else */ }

{ /* modal is here but it is hidden */ }
<Modal open={this.state.showModal}>...</Modal>

Alternatively, you can just skip the modal rendering at all until the showModal becomes true.

this.state.showModal && <Modal open>...</Modal>

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