Jenkins 管道实用程序步骤 - zip zipFile [英] Jenkins Pipeline Utility Steps - zip zipFile

问题描述

我正在尝试使用管道脚本压缩作为我的 jenkins 管道作业的输出创建的文件夹.通过谷歌搜索，我认识了 Jenkins

<块引用>

管道实用程序步骤 - zip zipFile

https:///jenkins.io/doc/pipeline/steps/pipeline-utility-steps/#code-zip-code-create-zip-file 压缩文件夹/文件，但无法获得精确的压缩管道语法.p>

在我的工作工作区中，我有一个名为Test"的文件夹，其中有 2 个子文件夹分别为Test1"和Test2".每个子文件夹都有 .dll 文件.所以，我想用所有子文件夹压缩整个测试"文件夹.

node(Jenkinks_1){回声邮编"zip zipFile: 'Test.zip', 目录:'C:\workspace\Build_Sample\Test'回声结束 - 邮编"}

以下是 Jenkins 的控制台输出:

由用户 XXXXX 发起[管道] 节点在 C:workspaceBuild_Sample 中的 Jenkins_1 上运行[管道] {[管道] 回声压缩[管道] 回声结束 - 邮编[管道] }[管道]//节点[管道] 管道结束完成:成功

寻找一些使用管道语法压缩文件夹的指导.感谢您的投入.

我想压缩一些文件作为我的 jenkins 管道作业的输出

解决方案

首先，分阶段分步尝试相同的操作，如这里:

管道{代理任何阶段{阶段('推送工件'){脚步 {sh 'mkdir 存档'sh'echo 测试 >存档/test.txt'zip zipFile:'test.zip'，存档:假，目录:'存档'archiveArtifacts 工件:'test.zip'，指纹:真}}...}

它使用 archiveArtifacts 来记录结果.

如果现在可以使用绝对路径，请尝试使用相对路径 ('..')

正如 OP Sri 所见，zip zipFile 是其中的一部分，并且需要JENKINS 管道实用程序步骤插件.
请参阅实施步骤".

---

关于用于多条件文件选择的语法，NicolasW 注释 在评论中指出 文档含糊不清:使用 glob ant-style 语法"...
不过，他用逗号分隔的基本语法让它工作了.
例如

zip zipFile: 'test.zip', archive: false, glob: 'config-/**/,scripts/**/*.*

但是，正如 Tanvir 所述/jenkins-pipeline-utility-steps-zip-zipfile/48353127?noredirect=1#comment118334240_48353127">评论, issue 44078 表示您需要将 zip 替换为:

 script{ zip zipFile: 'test.zip', archive: false, dir: 'archive' }

意味着您需要使用 script 块.

I am trying to zip the folders which are created as output of my jenkins pipeline job using pipeline script. By googling i came to know the Jenkins

Pipeline Utility Steps - zip zipFile

https://jenkins.io/doc/pipeline/steps/pipeline-utility-steps/#code-zip-code-create-zip-file to zip folders/files but could not get exact pipeline syntax to zip.

In my job workspace, I have a folder by name 'Test' which has 2 sub folders as 'Test1', 'Test2'. Each sub folder will have .dll files. So, I would like to zip entire 'Test' folder with all subfolder.

node(Jenkinks_1)
{
    echo "ZIP"
    zip zipFile: 'Test.zip', dir:'C:\workspace\Build_Sample\Test'
    echo "END - ZIP"
}

Below are the Console Output from Jenkins:

Started by user XXXXX
[Pipeline] node
Running on Jenkinks_1 in C:workspaceBuild_Sample
[Pipeline] {
[Pipeline] echo
ZIP
[Pipeline] echo
END - ZIP
[Pipeline] }
[Pipeline] // node
[Pipeline] End of Pipeline
Finished: SUCCESS

Looking for some guidance to zip the folders using pipeline syntax. Appreciate your inputs.

I wanted to zip some files as output of my jenkins pipeline job

解决方案

First, try the same operation in stages and step, as in here:

pipeline {
    agent any
    stages {
        stage ('push artifact') {
            steps {
                sh 'mkdir archive'
                sh 'echo test > archive/test.txt'
                zip zipFile: 'test.zip', archive: false, dir: 'archive'
                archiveArtifacts artifacts: 'test.zip', fingerprint: true
            }
        }
        ...
    }

It uses archiveArtifacts to record the result.

If using an absolute path does now work, try a relative one ('..')

As seen by the OP Sri, zip zipFile is part of, and requires the JENKINS Pipeline Utility Steps Plugin.
See "Implemented Steps".

---

Regarding the syntax to be used for multi-criteria file selection, NicolasW notes in the comments that the documentation is vague: "use glob ant-style syntax"...
He got it to work though, with a basic coma separated syntax.
E.g.

zip zipFile: 'test.zip', archive: false, glob: 'config-/**/,scripts/**/*.*

But, as noted by Tanvir in the comments, issue 44078 means you need to replace zip by:

                 script{ zip zipFile: 'test.zip', archive: false, dir: 'archive' }

Meaning you need to use a script block.

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