jqGrid 根据单元格值在 Grid 中为整行着色 [英] jqGrid Coloring an entire line in Grid based upon a cells value

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问题描述

I know it's been asked before, but I cant get it to run and I'm out of things to try.

I want to colorize a row in a Grid if its value is not 1 - I use a custom formatter for this. The formatter itself works, that's not the problem.

I've tried multiple ways I've found so far on the web - adding a class, directly adding CSS code, using setRowData, using setCell....

Here are my examples - none of them worked for me (Linux, ff363) - any pointer would be greatly appreciated.

27.05.2010_00:00:00-27.05.2010_00:00:00 is my row id

<style>
.state_inactive {
            background-color: red !important;
        }
.state_active {
    background-color: green !important;
}
</style>

function format_state (cellvalue, options, rowObject)
{
    var elem='#'+options.gid;
    if (cellvalue != 1) {

        jQuery('#list2').setRowData(options.rowID,'',
                                    {'background-color':'#FF6F6F'});

        jQuery('#list2').setRowData('27.05.2010_00:00:00-27.05.2010_00:00:00',
                                    '',{'background-color':'#FF6F6F'});

        for (var cnt=0;cnt<rowObject.length;cnt=cnt+1) {
            jQuery(elem).setCell(options.rowId,cnt,'','state_inactive','');

            jQuery(elem).setCell('"'+options.rowId+'"',cnt,'','state_inactive');

            jQuery(elem).setCell('"'+options.rowId+'"',cnt,'5',
                                 {'background-color':'#FF6F6F'},'');
        }
    } else {
        for (var cnt=0;cnt<rowObject.length;cnt=cnt+1) {
            jQuery(elem).setCell(options.rowId,cnt,'','state_active','');
        }
    }
    <!-- dont modify, we simply added the class above-->
    return cellvalue;
}

解决方案

It seems to me that your main problem is you're not setting a 'background-color' style. You should remove 'ui-widget-content' class from the row (from <tr> element)

jQuery("#"+ options.rowId,jQuery('#list2')).removeClass('ui-widget-content');

before adding the class state_activ or state_inactive, because jQuery UI class 'ui-widget-content' is define .ui-widget-content like

{
border: 1px solid #fad42e;
background: #fbec88 url(images/ui-bg_flat_55_fbec88_40x100.png) 50% 50% repeat-x;
color: #363636;
}

and only with setting of CSS 'background-color' your not really change the background color. So try to use something like

var trElement = jQuery("#"+ options.rowId,jQuery('#list2'));
trElement.removeClass('ui-widget-content');
trElement.addClass('state_active');

这篇关于jqGrid 根据单元格值在 Grid 中为整行着色的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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