增加 IP 地址 [英] Increment IP address

问题描述

在那个程序中，我想增加 IP 地址.我看到这样的输出:

In that program I want to increment IP address. And I see output like that:

125.23.45.67
126.23.45.67
127.23.45.67 
128.23.45.67
129.23.45.67
130.23.45.67
131.23.45.67
132.23.45.67
133.23.45.67
134.23.45.67

但我想看到这样的输出:

But I want to see output like this:

124.23.45.67
124.23.45.68
124.23.45.68 
124.23.45.70
124.23.45.71
124.23.45.72
124.23.45.73
124.23.45.74
124.23.45.75
124.23.45.76

这是程序代码:

#include <stdlib.h>
#include <stdio.h>
#include <iostream>
using namespace std;
#include "winsock2.h"
#pragma comment(lib,"wsock32.lib")

void main()
{
in_addr adr1;
in_addr adr2;
int i;

adr1.s_addr=inet_addr("124.23.45.67");
adr2.s_addr=inet_addr("as.34.34.56");
if (adr1.s_addr!=INADDR_NONE)
    cout << " adr1 correct" << endl;
else
    cout << " adr1 incorect " << endl;

if (adr2.s_addr!=INADDR_NONE)
    cout << " adr2 correct" << endl;
else
    cout << " adr2 incorect" << endl;

cout << inet_ntoa(adr1) << endl;
cout << inet_ntoa(adr2) << endl;

for (i=0;i<10;i++)
{
    adr1.s_addr ++;
    cout << inet_ntoa(adr1) << endl;
}
}

推荐答案

Big endian 和 little endian 又多了一个！使用 htonl 和 ntohl 来回转换.

Big endian and little endian gets another one! Use htonl and ntohl to convert back and forth.

for (i=0;i<10;i++)
{
    adr1.s_addr  = htonl(ntohl(adr1.s_addr) + 1);

    cout << inet_ntoa(adr1) << endl;
}

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