sequelize.query() 两次返回相同的结果 [英] sequelize.query() returns same result twice

问题描述

我正在使用 sequelize 连接 mysql 数据库的 nodejs 项目中工作.我还使用 sequelize-values 从 Sequelize 实例中获取原始数据.

I am working in nodejs project in that using sequelize for connecting mysql database. I am also using sequelize-values for getting raw data from Sequelize instances.

我已经写了下面的代码

var Sequelize = require('sequelize');
require('sequelize-values')(Sequelize);
var sequelizeObj = new Sequelize('mysql://root:@localhost/database');

sequelizeObj.authenticate().then(function (errors) {
    console.log(errors)
});

sequelizeObj.query("SELECT * FROM `reports` WHERE `id` = 1200").then(function (result) {

    });

现在reports表只有1条记录id 1200，但是result给出了相同记录的两个对象，意味着两条记录都是与 id 1200 相同.

Now the table reports have only 1 record for id 1200, But the result gives two objects for same records, Means both records are same of id 1200.

[ [ { id: 1200,
  productivity_id: 9969,
  gross_percentage_points: 100 } ],
[ { id: 1200,
  productivity_id: 9969,
  gross_percentage_points: 100 } ] ]

让我知道我做错了什么?

Let me know what I am doing wrong?

推荐答案

第一个对象是结果对象，第二个是元数据对象(包含受影响的行等) - 但在 mysql 中，这两者是相等的.

The first object is the result object, the second is the metadata object (containing affected rows etc) - but in mysql, those two are equal.

传递 { type: Sequelize.QueryTypes.SELECT } 作为第二个参数会给你一个结果对象(元数据对象省略

Passing { type: Sequelize.QueryTypes.SELECT } as the second argument will give you a single result object (metadata object omitted

https://github.com/sequelize/sequelize/wiki/Upgrading-to-2.0#changes-to-raw-query

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